Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Aim: To implement a program for following string operations:
Code:
class String
{
char str[50];
public:
String();
void getdata();
int length1();
void concat(String s);
String substring(int ind, int len);
char charAt(int ind);
int indexOf(char ch);
String reverse();
void display();
};
void String::display()
cout< } void String::getdata() { gets(str); } String::String() { strcpy(str,""); } int String::length1() { int l; l=strlen(str); return (l); } void String::concat(String s) { strcat(str,s.str); } String String::substring(int ind, int len) { int l,x,m; char su[50]; String sub; strcpy(sub.str,""); for(x=ind,m=0;x<=len+1;x++,m++) { su[m]=str[x]; } su[m]='\0'; strcpy(sub.str,su); return (sub); } char String::charAt(int ind) { char c=' '; int l=strlen(str); if(ind>l) cout<<"Position out of Bounds"; else c=str[ind]; return (c); } int String::indexOf(char ch) { int x=1; while(str[x]!=ch && str[x]!='\0') x++; if(str[x]!=ch) return (-1); else return (x); } String String::reverse() { String s; strcpy(s.str,str); strrev(s.str); return (s); } void main() { clrscr(); String s1,s2,s3,s4; cout<<"Enter string 1:"; s1.getdata(); cout<<"\n\nEnter string 2:"; s2.getdata(); char ch='o'; int l=s1.length1(); cout<<"\n\nLength of string: '"; s1.display(); cout<<" 'is "< s1.concat(s2); cout<<"\n\nAfter concatenation:"; s1.display(); int ind=2, len=4; cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
}
void String::getdata()
gets(str);
String::String()
strcpy(str,"");
int String::length1()
int l;
l=strlen(str);
return (l);
void String::concat(String s)
strcat(str,s.str);
String String::substring(int ind, int len)
int l,x,m;
char su[50];
String sub;
strcpy(sub.str,"");
for(x=ind,m=0;x<=len+1;x++,m++)
su[m]=str[x];
su[m]='\0';
strcpy(sub.str,su);
return (sub);
char String::charAt(int ind)
char c=' ';
int l=strlen(str);
if(ind>l)
cout<<"Position out of Bounds";
else
c=str[ind];
return (c);
int String::indexOf(char ch)
int x=1;
while(str[x]!=ch && str[x]!='\0')
x++;
if(str[x]!=ch)
return (-1);
return (x);
String String::reverse()
String s;
strcpy(s.str,str);
strrev(s.str);
return (s);
void main()
clrscr();
String s1,s2,s3,s4;
cout<<"Enter string 1:";
s1.getdata();
cout<<"\n\nEnter string 2:";
s2.getdata();
char ch='o';
int l=s1.length1();
cout<<"\n\nLength of string: '";
s1.display();
cout<<" 'is "< s1.concat(s2); cout<<"\n\nAfter concatenation:"; s1.display(); int ind=2, len=4; cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s1.concat(s2);
cout<<"\n\nAfter concatenation:";
int ind=2, len=4;
cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s3.display();
char c=s1.charAt(ind+4);
cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
int i=s1.indexOf(ch);
cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s4=s1.reverse();
cout<<"\n\nReverse of \n\t'";
cout<<"'\n\t\tis \n\t";
s4.display();
getch();
Output:
Enter string 1: Ankit Goyal is
Enter string 2: a student of VESIT.
Length of string: 'Ankit Goyal is ' is 14
After concatenation: Ankit Goyal is a student of VESIT.
Start Index=2
Length of Substring=4
Substring: kit
Character at Index: 6 is 'G'
Index of 'o' is: 7
Reverse of
'Ankit Goyal is a student of VESIT.'
is
.TISEV fo tneduts a si layoG tiknA
#question.conversion of tree into binary tree.
pebblemerchant
char P[100]; double X=533.8*22500; sprintf(P,"%f %u",X,(unsigned int)X); MessageBox(P,"SSS"); //12010500.000 12010499
Ask question #Miniasdasmum 100 words accepted#
want a c code soon
Project Description: We are looking to have software that we will use to track employee information regarding our wellness program. We would like the system to be able to follow
make use of class objects two calculate average
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b.
Write a program that performs character processing on 10 characters read in from a file, and writes the results to output files. Do NOT use loops or arrays to solve this problem. N
Operator Overloading Fundamentals The C language uses the concept of Operator Overloading discreetly. The asterisk (*) is used as multiplication operator as well as indirect
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd