Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Aim: To implement a program for following string operations:
Code:
class String
{
char str[50];
public:
String();
void getdata();
int length1();
void concat(String s);
String substring(int ind, int len);
char charAt(int ind);
int indexOf(char ch);
String reverse();
void display();
};
void String::display()
cout< } void String::getdata() { gets(str); } String::String() { strcpy(str,""); } int String::length1() { int l; l=strlen(str); return (l); } void String::concat(String s) { strcat(str,s.str); } String String::substring(int ind, int len) { int l,x,m; char su[50]; String sub; strcpy(sub.str,""); for(x=ind,m=0;x<=len+1;x++,m++) { su[m]=str[x]; } su[m]='\0'; strcpy(sub.str,su); return (sub); } char String::charAt(int ind) { char c=' '; int l=strlen(str); if(ind>l) cout<<"Position out of Bounds"; else c=str[ind]; return (c); } int String::indexOf(char ch) { int x=1; while(str[x]!=ch && str[x]!='\0') x++; if(str[x]!=ch) return (-1); else return (x); } String String::reverse() { String s; strcpy(s.str,str); strrev(s.str); return (s); } void main() { clrscr(); String s1,s2,s3,s4; cout<<"Enter string 1:"; s1.getdata(); cout<<"\n\nEnter string 2:"; s2.getdata(); char ch='o'; int l=s1.length1(); cout<<"\n\nLength of string: '"; s1.display(); cout<<" 'is "< s1.concat(s2); cout<<"\n\nAfter concatenation:"; s1.display(); int ind=2, len=4; cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
}
void String::getdata()
gets(str);
String::String()
strcpy(str,"");
int String::length1()
int l;
l=strlen(str);
return (l);
void String::concat(String s)
strcat(str,s.str);
String String::substring(int ind, int len)
int l,x,m;
char su[50];
String sub;
strcpy(sub.str,"");
for(x=ind,m=0;x<=len+1;x++,m++)
su[m]=str[x];
su[m]='\0';
strcpy(sub.str,su);
return (sub);
char String::charAt(int ind)
char c=' ';
int l=strlen(str);
if(ind>l)
cout<<"Position out of Bounds";
else
c=str[ind];
return (c);
int String::indexOf(char ch)
int x=1;
while(str[x]!=ch && str[x]!='\0')
x++;
if(str[x]!=ch)
return (-1);
return (x);
String String::reverse()
String s;
strcpy(s.str,str);
strrev(s.str);
return (s);
void main()
clrscr();
String s1,s2,s3,s4;
cout<<"Enter string 1:";
s1.getdata();
cout<<"\n\nEnter string 2:";
s2.getdata();
char ch='o';
int l=s1.length1();
cout<<"\n\nLength of string: '";
s1.display();
cout<<" 'is "< s1.concat(s2); cout<<"\n\nAfter concatenation:"; s1.display(); int ind=2, len=4; cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s1.concat(s2);
cout<<"\n\nAfter concatenation:";
int ind=2, len=4;
cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s3.display();
char c=s1.charAt(ind+4);
cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
int i=s1.indexOf(ch);
cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s4=s1.reverse();
cout<<"\n\nReverse of \n\t'";
cout<<"'\n\t\tis \n\t";
s4.display();
getch();
Output:
Enter string 1: Ankit Goyal is
Enter string 2: a student of VESIT.
Length of string: 'Ankit Goyal is ' is 14
After concatenation: Ankit Goyal is a student of VESIT.
Start Index=2
Length of Substring=4
Substring: kit
Character at Index: 6 is 'G'
Index of 'o' is: 7
Reverse of
'Ankit Goyal is a student of VESIT.'
is
.TISEV fo tneduts a si layoG tiknA
convert string s into palindrome by doing character replacement
Write a function that has two int parameters num and n, and returns TRUE when the nth bit in num is 1, otherwise FALSE. This function should use the function in the above problem.
Given an integer n and a permutation of numbers 1, 2 ... , n-1, n write a program to print the permutation that lexicographically precedes the given input permutation. If the given
One person who is specialist at programming and solving problems with a computer Project Description: Dear Potential computer, hardware, programming and software genius, I
C Program to check PRIME NUMBERS main() { int i,k,r,flag; clrscr(); printf("ENTER THE NO. TO CHECK IT IS PRIME OR NOT: ");
THIS PROGRAM IS TO COMPARE THE TWO DATES GIVEN BY THE USER #include #include #include struct date { int dd; int mm; int yy; }; date compare(date d1,date d2) {
#pebblemerchant.h
Need Squid Web Proxy with ffmpeg to convert flv to h.264 Project Description: We need a squid proxy setup with the modification that will transcode FLV to h.264 in real-time,
Q: Tells the operators one can override; which operators should he override? A: Bottom line: don't puzzle your users. Remember the reason of operator overloading: to decreas
# include stdio.h> # include conio.h> # include string.h> void main() { int i=0,j=0; char a[100],temp; clrscr();
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd