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Aim: To implement a program for following string operations:
Code:
class String
{
char str[50];
public:
String();
void getdata();
int length1();
void concat(String s);
String substring(int ind, int len);
char charAt(int ind);
int indexOf(char ch);
String reverse();
void display();
};
void String::display()
cout< } void String::getdata() { gets(str); } String::String() { strcpy(str,""); } int String::length1() { int l; l=strlen(str); return (l); } void String::concat(String s) { strcat(str,s.str); } String String::substring(int ind, int len) { int l,x,m; char su[50]; String sub; strcpy(sub.str,""); for(x=ind,m=0;x<=len+1;x++,m++) { su[m]=str[x]; } su[m]='\0'; strcpy(sub.str,su); return (sub); } char String::charAt(int ind) { char c=' '; int l=strlen(str); if(ind>l) cout<<"Position out of Bounds"; else c=str[ind]; return (c); } int String::indexOf(char ch) { int x=1; while(str[x]!=ch && str[x]!='\0') x++; if(str[x]!=ch) return (-1); else return (x); } String String::reverse() { String s; strcpy(s.str,str); strrev(s.str); return (s); } void main() { clrscr(); String s1,s2,s3,s4; cout<<"Enter string 1:"; s1.getdata(); cout<<"\n\nEnter string 2:"; s2.getdata(); char ch='o'; int l=s1.length1(); cout<<"\n\nLength of string: '"; s1.display(); cout<<" 'is "< s1.concat(s2); cout<<"\n\nAfter concatenation:"; s1.display(); int ind=2, len=4; cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
}
void String::getdata()
gets(str);
String::String()
strcpy(str,"");
int String::length1()
int l;
l=strlen(str);
return (l);
void String::concat(String s)
strcat(str,s.str);
String String::substring(int ind, int len)
int l,x,m;
char su[50];
String sub;
strcpy(sub.str,"");
for(x=ind,m=0;x<=len+1;x++,m++)
su[m]=str[x];
su[m]='\0';
strcpy(sub.str,su);
return (sub);
char String::charAt(int ind)
char c=' ';
int l=strlen(str);
if(ind>l)
cout<<"Position out of Bounds";
else
c=str[ind];
return (c);
int String::indexOf(char ch)
int x=1;
while(str[x]!=ch && str[x]!='\0')
x++;
if(str[x]!=ch)
return (-1);
return (x);
String String::reverse()
String s;
strcpy(s.str,str);
strrev(s.str);
return (s);
void main()
clrscr();
String s1,s2,s3,s4;
cout<<"Enter string 1:";
s1.getdata();
cout<<"\n\nEnter string 2:";
s2.getdata();
char ch='o';
int l=s1.length1();
cout<<"\n\nLength of string: '";
s1.display();
cout<<" 'is "< s1.concat(s2); cout<<"\n\nAfter concatenation:"; s1.display(); int ind=2, len=4; cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s1.concat(s2);
cout<<"\n\nAfter concatenation:";
int ind=2, len=4;
cout<<"\n\nStart Index="< s3.display(); char c=s1.charAt(ind+4); cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s3.display();
char c=s1.charAt(ind+4);
cout<<"\n\nCharacter at Index: "< int i=s1.indexOf(ch); cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
int i=s1.indexOf(ch);
cout<<"\n\nIndex of '"< s4=s1.reverse(); cout<<"\n\nReverse of \n\t'"; s1.display(); cout<<"'\n\t\tis \n\t"; s4.display(); getch(); } Output: Enter string 1: Ankit Goyal is Enter string 2: a student of VESIT. Length of string: 'Ankit Goyal is ' is 14 After concatenation: Ankit Goyal is a student of VESIT. Start Index=2 Length of Substring=4 Substring: kit Character at Index: 6 is 'G' Index of 'o' is: 7 Reverse of 'Ankit Goyal is a student of VESIT.' is .TISEV fo tneduts a si layoG tiknA
s4=s1.reverse();
cout<<"\n\nReverse of \n\t'";
cout<<"'\n\t\tis \n\t";
s4.display();
getch();
Output:
Enter string 1: Ankit Goyal is
Enter string 2: a student of VESIT.
Length of string: 'Ankit Goyal is ' is 14
After concatenation: Ankit Goyal is a student of VESIT.
Start Index=2
Length of Substring=4
Substring: kit
Character at Index: 6 is 'G'
Index of 'o' is: 7
Reverse of
'Ankit Goyal is a student of VESIT.'
is
.TISEV fo tneduts a si layoG tiknA
demonstrates shearing about origin
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