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In this sorting algorithm, multiple swapping occurs in one pass. Smaller elements move or 'bubble' up to the top of the list, so the name given to the algorithm.
In this method, adjacent members of list to be sorted are compared. If item over the top is greater than the item instantly below it, then they are swapped. This procedure is carried on until the list is sorted.
The detailed algorithm is like as:
Algorithm: BUBBLE SORT
1. Begin
2. Read the n elements
3. for i=1 to n
for j=n downto i+1
if a[j] <= a[j-1]
swap(a[j],a[j-1])
4. End // of Bubble Sort
Total number of comparisons in Bubble sort will be:
= (N-1) +(N-2) . . . + 2 + 1
= (N-1)*N / 2 =O(N2)
This inefficiency is because of the fact that an item moves only to the next position in each pass.
Post-order Traversal This can be done both iteratively and recursively. The iterative solution would need a change of the in-order traversal algorithm.
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Two linked lists are having information of the same type in ascending order. Write down a module to merge them to a single linked list that is sorted merge(struct node *p, stru
pls i want a psuedo code for hotel reservation system.
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Q. Give the adjacency matrix for the graph drawn below: Ans: Adjacency matrix for the graph given to us
Ask question #Minimum 1cepted#
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