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In this sorting algorithm, multiple swapping occurs in one pass. Smaller elements move or 'bubble' up to the top of the list, so the name given to the algorithm.
In this method, adjacent members of list to be sorted are compared. If item over the top is greater than the item instantly below it, then they are swapped. This procedure is carried on until the list is sorted.
The detailed algorithm is like as:
Algorithm: BUBBLE SORT
1. Begin
2. Read the n elements
3. for i=1 to n
for j=n downto i+1
if a[j] <= a[j-1]
swap(a[j],a[j-1])
4. End // of Bubble Sort
Total number of comparisons in Bubble sort will be:
= (N-1) +(N-2) . . . + 2 + 1
= (N-1)*N / 2 =O(N2)
This inefficiency is because of the fact that an item moves only to the next position in each pass.
Give an algorithm to find both the maximum and minimum of 380 distinct numbers that uses at most 568 comparisons.
Normally a potential y satisfies y r = 0 and 0 ³ y w - c vw -y v . Given an integer K³0, define a K-potential to be an array y that satisfies yr = 0 and K ³ y w - c vw -y v
The number of interchanges needed to sort 5, 1, 6, 2 4 in ascending order using Bubble Sort is 5
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