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Question 1 An experiment succeeds twice as often as it fails. Find the chance that in the next six trials there will be at least four successes
Question 2 An insurance company has discovered that only about 0.1% of the population is involved in a certain type of accident each year. If its 10000 policy holders were randomly selected from the population, what is the probability that not more than 5 of its clients are involved in such an accident next year?
Question 3 Briefly explain Markov chains
Evaluate following limits. Solution Let's begin with the right-hand limit. For this limit we have, x > 4 ⇒ 4 - x 3 = 0 also, 4 - x → 0 as x → 4
L.H.S. =cos 12+cos 60+cos 84 =cos 12+(cos 84+cos 60) =cos 12+2.cos 72 . cos 12 =(1+2sin 18)cos 12 =(1+2.(√5 -1)/4)cos 12 =(1+.(√5 -1)/2)cos 12 =(√5 +1)/2.cos 12 R.H.S =c
Definition 1. Given any x 1 & x 2 from an interval I with x 1 2 if f ( x 1 ) 2 ) then f ( x ) is increasing on I. 2. Given any x 1 & x 2 from an interval
v=u+at s=ut+1/2at^2
A Stone is dropped from the top of the tower and travel 24.5 m in last second of its journey. the height of the tower is ...?
Solve the subsequent proportion: Example: Solve the subsequent proportion for x. Solution: 5:x = 4:15 The product of the extremes is (5)(15) = 75. The produ
Solve -10 cos(3t )= 7 on [-2,5]. Solution Let's first get the inverse cosine portion of this problem taken care of. cos(3 t )= - 7/10 ⇒ 3t = cos -1 ( - 7
what is the value of integration limit n-> infinity [n!/n to the power n]to the power 1/n Solution) limit n-->inf. [1 + (n!-n^n)/n^n]^1/n = e^ limit n-->inf. {(n!-n^n)
The probability that a leap year will have 53 sunday is ? and how please explain it ? (a)1/7 (b) 2/7 (c) 5/7 (d)6/7 Sol) A leap year has 366 days, therefore 52 weeks i.e
can anyone explain me the concept of quadratic equation?
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