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1. Write two m-files, one for the bisection method and another for Newton's method.
2. Using both the Bisection method and the Newton method answer the following:
Include the commands you typed into Matlab
a) Find the root to 3, 5, and 8 decimal places of f(x) = x2- 2 starting with an initial approximation of x=1.
b) How many steps did it take for the bisection method to find the root to 3, 5, and 8 decimal places?
c) How many steps did it take for the Newton method to find the root to 3, 5 and 8 decimal places?
3. Use Newton's method to find all the real roots of f(x) = x5+ x4 -4x3 - 3x2- 3x +1
4. Apply Newton's method to the function f(x) = x3 - x with an initial approximation of x=1/√5. Is the method converging? What happens? Explain your answer using the graph of f(x).
5. Use Newton's method on the function (x) = 3√5 . What happens when your initial approximation is not x=0? Explain your answer using the graph of f(x).
IF 7 AND 2 ARE TWO ROOTS OF THE EQUATION |X 3 7 2 X 2 7 6 X |=0 THEN FIND THE THIRD ROOT IS
Differences of Squares (and other even powers) ? A square monomial is a monomial which is the square of another monomial. Here are some examples: 25 is the square of 5 x 2 i
find the magnitude of the following vectors:5i+7j
Draw a line segment AB of length 4.4cm. Taking A as centre, draw a circle of radius. 2cm and taking B as centre, draw another circle of radius 2.2cm. Construct tangents to each cir
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no the parallel lines do not meet at infinity because the parallel lines never intersect each other even at infinity.if the intersect then it is called perpendicuar lines
reduction
Leo works at the Bagel Shop after school and on Saturdays. He is paid $4.00 per hour after school and $5.00 per hour on Saturday. Last week Leo worked a total of 12 hours and made
Natural exponential function : There is a extremely important exponential function which arises naturally in several places. This function is called as the natural exponential fun
Solve the subsequent IVP and find the interval of validity for the solution. y' + (4/x) y = x 3 y 2 , y(2) = - 1, x > 0 Solution Thus, the first thing that we re
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