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Binary tree creation
struct NODE
{
struct NODE *left;
int value;
struct NODE *right;
};
create_tree( struct NODE *curr, struct NODE *new )
if(new->value <= curr->value)
if(curr->left != NULL)
create_tree(curr->left, new);
else
curr->left = new;
}
if(curr->right != NULL)
create_tree(curr->right, new);
curr->right = new;
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Q. Prove the hypothesis that "A tree having 'm' nodes has exactly (m-1) branches". Ans: A tree having m number of nodes has exactly (m-1) branches Proof: A root
The fundamental element of linked list is a "record" structure of at least two fields. The object which holds the data & refers to the next element into the list is called a node .
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Let G=(V,E) be a graph for which all nodes have degree 5 and where G is 5-edge is connected. a) Show that the vector x which is indexed by the edges E and for which xe = 1/5 for
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