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Binary tree creation
struct NODE
{
struct NODE *left;
int value;
struct NODE *right;
};
create_tree( struct NODE *curr, struct NODE *new )
if(new->value <= curr->value)
if(curr->left != NULL)
create_tree(curr->left, new);
else
curr->left = new;
}
if(curr->right != NULL)
create_tree(curr->right, new);
curr->right = new;
Example: Assume the following of code: x = 4y + 3 z = z + 1 p = 1 As we have been seen, x, y, z and p are all scalar variables & the running time is constant irrespective
Postorder traversal of a binary tree struct NODE { struct NODE *left; int value; /* can take any data type */ struct NODE *right; }; postorder(struct NODE
for(int i = 0; i for (int j = n - 1; j >= i ; j--){ System.out.println(i+ " " + j);
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Q. Using the following given inorder and preorder traversal reconstruct a binary tree Inorder sequence is D, G, B, H, E, A, F, I, C
Write a program that uses the radix sort to sort 1000 random digits. Print the data before and after the sort. Each sort bucket should be a linked list. At the end of the sort, the
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