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Binary tree creation
struct NODE
{
struct NODE *left;
int value;
struct NODE *right;
};
create_tree( struct NODE *curr, struct NODE *new )
if(new->value <= curr->value)
if(curr->left != NULL)
create_tree(curr->left, new);
else
curr->left = new;
}
if(curr->right != NULL)
create_tree(curr->right, new);
curr->right = new;
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If a node in a BST has two children, then its inorder predecessor has No right child
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