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A Binary Search Tree is binary tree which is either empty or a node having a key value, left child & right child.
By analyzing the above definition, we notice that BST comes into two variants namely empty BST & non-empty BST.
The empty BST contain no added structure, whereas the non-empty BST contain three components.
The non-empty BST satisfies the given conditions:
a) The key within the left child of node (if exists) is less than the key in its parent node.
b) The key within the right child of a node (if exists) is greater than the key in its parent node.
c) The left & right sub trees of the root are binary search trees again.
The given are some operations which can be performed on Binary search trees:
How do collisions happen during hashing? Usually the key space is much larger than the address space, thus, many keys are mapped to the same address. Assume that two keys K1 an
Q. Write down an algorithm to evaluate an expression given to you in postfix notation. Show the execution of your algorithm for the following given expression. AB^CD-EF/GH+/+*
Any binary search tree must contain following properties to be called as a red-black tree. 1. Each node of a tree should be either red or black. 2. The root node is always bl
7. String manipulation 7.a Write a C Program using following string manipulation functions a) strcpy b) strncpy c) strcmp d) strncmp e) strlen f) strcat
algorithm for multiple queue with example program
What are the languages which support assertions Languages which support assertions often provide different levels of support. For instance, Java has an assert statement which t
The most common way to insert nodes to a general tree is to first discover the desired parent of the node you desire to insert, and then insert the node to the parent's child list.
B i n a ry Search Algorithm is given as follows 1. if (low > high) 2. return (-1) 3. mid = (low +high)/2; 4. if ( X = = a [mid]) 5. return (mid); 6.
What are the expression trees? Represent the below written expression using a tree. Give a relevant comment on the result that you get when this tree is traversed in Preorder,
bfs and dfs
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