Binary compounds: simple structures, Chemistry

Assignment Help:

 

Coordination number and geometry

 

Binary compounds are ones with two different elements present. 'Simple' crystal structures can be classed as ones in which each atom (or ion) is surrounded in a regular way by atoms (or ions) of the other kind. Even with this limited existence many structures are possible.

Although many are achieved with ionic compounds, some of these structures are shown by compounds with covalent bonding, and a discussion of the bonding factors involved in favoring one structure rather than another is deferred to

When the two elements B and A are not equivalent A is drawn smaller and with shading. In ionic compounds this is more general the metallic (cationic) element. If the role of cations and anions is reversed we speak of the anti-structure: thus Li2O has the, Cs2O the anti-CdI2 structure and anti-fluorite (CaF2) structure.

From the local point of view of each atom the most important characteristics of a structure are the coordination geometry and coordination number (CN). In the examples described these are the same for all atoms of the same type. Coordination numbers can be compatible with the stoichiometry. In AB both B and A have the same CN, the examples shown being

 

Zinc blende (4:4); Rocksalt (6:6); NiAs (6:6); CsCl (8:8).

 

When the stoichiometry is AB2 the CN of A has to be twice that of B:

Rutile (6:3); CdI2 (6:3); Fluorite (8:4).

 

 

 

 

 

 

2292_Untitled.png

 

 

Fig. 1. A selection of binary structures.

In the structures illustrate many of the atoms have regular coordination geometry:

 

CN=2: linear (B in ReO3);

 

CN=3: planar (B in rutile);

 

CN=4: tetrahedral (A and B in zinc blende, B in fluorite);

 

CN=6: octahedral (A and B in rocksalt, A in NiAs, rutile and CdI2);

 

CN=8: cubic (A and B in CsCl, A in fluorite).

 


Related Discussions:- Binary compounds: simple structures

Energy of the electron in hydrogen atom is given, Energy of the electron in...

Energy of the electron in Hydrogen atom is given by: (1) E n = 131.38/ n 2 x kj mol -1         (2)  E n = 131.33/n xkj mol -1           (3) E n = 1313.3/ n 2 x kj mol

The number of orbitals in the fourth principal quantum no., The number of o...

The number of orbitals in the fourth principal quantum number will be: (1) 4               (2) 8        (3) 12               (4) 16 Ans: 16

Metelurgy, general principle on metelurgy

general principle on metelurgy

Prefixes, why we consider methyl using prefixes?

why we consider methyl using prefixes?

Quantitative determination of ion, Quantitative determination of a number o...

Quantitative determination of a number of ions like Cu, Ag, Zn, Fe, Ni, Co, Cd etc. has been done by using 1.2.3-benztiazole as precipitating agent under different experimental c

Acetone react with (i)mg/h2o (ii)h2so4, This is an example of pinacone pina...

This is an example of pinacone pinacone rearrangemnt acetone with Mg and H2O forms 2,3 Dimethylbutane2.3 diol which on reacting with H+ from forms first a carbocation on carbon 2

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd