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Q. Binary Coded Decimal Addition
Now as in conventional decimal addition, Binary Coded Decimal addition is performed one decimal digit at a time.
What happens when the sum go above what can be represented in 4 bits?
What are the circumstances under which a carry is generated to the next highest-order BCD digit?
For illustration, let's consider the addition of the two BCD digits 5 and 3:
Now consider the sum of 5 and 8:
The sum is 11012 = 13, but this result should be properly represented as 0001 0011 in Binary Coded Decimal notation. Auspiciously, there is a simple way to find the correct result. We add 6 (01102) to the digit sum if it exceeds 9
(
)
. Let's examine the following cases:
In the both cases, by adding six we obtain the correct answer in BCD.
find E*(s) for E(s)=1-e/s(s+1)
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