Basic microprocessor architecture and interface, Assembly Language

Assignment Help:

Basic Microprocessor Architecture and Interface :

Introduction:

Intel launches its first 4-bit microprocessor 4004 in the year 1971 and 8-bit microprocessor 8008 in the year 1972. These microprocessors could not carry on as general purpose microprocessors due to their and performance limitations and design. Launching of the first general purpose 8-bit microprocessor 8080 in the year 1974 by Intel is considered to  be  the  first  main  stepping   stone  towards  the development  of advanced  microprocessors. The microprocessor 8085 followed 8080, with a few more features included to its architecture, which resulted in a functionally full microprocessor.  The main restriction  of the 8-bit microprocessors  were their low speed of execution, low memory addressing capability, restricted  number of general purpose registers and a less powerful instruction set . All these restriction of the 8-bit microprocessors tempted the designers to go for more powerful processors in terms of advanced architecture, larger memory addressing capability, more processing capability, and a more powerful instruction set. The 8086 was a outcome of such developmental design efforts.

In the family of 16-bit microprocessors, Intel's 8086 was the first 1 launched in the year1978. The lancing of the 16-bit processor was a result of the increasing demand for more and more powerful and high speed computational resources.  8086 microprocessor has a much more powerful instruction set along with the architectural developments which imparted substantial programming improvement and flexibility in speed over the 8-bit microprocessors.

The peripheral chips designed earlier for 8085 were compatible with microprocessor 8086 with slight or no modifications. Although  there is a considerable  dissimilarity  between  the memory  addressing  techniques  of 8086  and  8085,  the  memory  interfacing  technique  is same,  but  includes  the  use of a few  additional signals.  The clock requirements are also different ascompared to 8085, but the wholeminimal system organization of 8086 is same to that of a general 8-bit microprocessor. In this chapter, the architectures of 8088 and 8086 are explained in enough details along with the interfacing of the supporting chips withthem to form a minimum system. The system organization is also explained in significant details for both the operating modes of 8088 and 8086, along with essential timing diagrams.

 

 


Related Discussions:- Basic microprocessor architecture and interface

Memory segmentation-microprocessor, Memory Segmentation : The  memory ...

Memory Segmentation : The  memory in an 8086/8088  based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n

Relocate program and data, ) What is the difference between re-locatable pr...

) What is the difference between re-locatable program and re-locatable data?

And-logical instruction-microprocessor, AND: Logical AND: This instruction...

AND: Logical AND: This instruction bit by bit ANDs the source operand that might be an immediate, or a memory location or register to the destination operand that might be a memor

Assembler directives and operators-microprocessor, Assembler Directives and...

Assembler Directives and Operators The major advantage of machine language programming is directly that the memory control is in the hands of the programmer, so that, he can be

#title, how i can write a program to divide 2 numbers

how i can write a program to divide 2 numbers

A/D conversions, A/D conversion: Basic tasks: (a) Write a program that wil...

A/D conversion: Basic tasks: (a) Write a program that will read and display the analog voltage on pin PE7 approximately once every second. (b) Write a program that will read and d

Div-idiv-arithmetic instruction-microprocessor, DIV: Unsigned Division:- T...

DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in t

Assignment, You have to write a subroutine (assembly language code using NA...

You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2

Physical memory mapped and port input output-microprocessor, Physical Memor...

Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd