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Prove that the Digraph of a partial order has no cycle of length greater than 1. Assume that there exists a cycle of length n ≥ 2 in the digraph of a partial order ≤ on a set A
How to solve this: log x(81) = 4
Without solving, find out the interval of validity for the subsequent initial value problem. (t 2 - 9) y' + 2y = In |20 - 4t|, y(4) = -3 Solution First, in order to u
-3+4 #Minimum 100 words accepted#
some basic vb codes withing excel to get things done quickly.
You are painting the surface of a silo that has a diameter of 16 ft and height of 50 ft. What is the net surface area to be painted? Consider the top of the silo is 1/2 a sphere
using the g.e matrix, how can you turn an unattractive product to be attractive
show that the green''s function for x"=0,x(1)=0,x''(0)+x''(1)=0 is G(t,s)=1-s
1. Suppose the arrival times of phone calls in a help centre follow a Poisson process with rate 20 per hour (so the inter-arrival times are independent exponential random variables
express each logariths in terms of log3 P and log3 Q. 1. log3 P^2 Q^3
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