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A non uniform rod AB has a mass M and length 2L the mas per unit length of the rod is mx at a point of the rod distant x from A.find the moment of inertia of this rod about an axis perpendicular to the rod (!)through A (2)through the mid point of ABAns) consider a strip of the rod ''dx'' at a length ''x'' from A.mass of the small strip is mx*dx.moment of inertia of the small strip about A IS m*x*dx*x*x.on integrating we get moment of inetia about A as 4*m*L*L*L*L.ABOUT MID POINT OF AB.consider a strip of length ''dx'' at a distance of x from mid point P.mass of it is m*(L-x)*dx.moment of inertia of half of the rod about P is m*(L-x)*dx*x*x.on integration we get moment of inertia of half of the rod.similarly do for the other half.adding them we get the answer.
Q. A capacitor of capacitance 2 μF is in an ac circuit of 1000 Hz. Compute the reactance of it. Solution: Capacitive reactance XC = 1 / ω C = 1 / 2π ν C =
why we use compensater??
An ideal Brayton cycle uses air as a working fluid. The air enters the compressor at 101 kpa and 37 C. The pressure ratio of the compressor is 12:1, and the temperature of the air
how rotational motion was investigate
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