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A non uniform rod AB has a mass M and length 2L the mas per unit length of the rod is mx at a point of the rod distant x from A.find the moment of inertia of this rod about an axis perpendicular to the rod (!)through A (2)through the mid point of ABAns) consider a strip of the rod ''dx'' at a length ''x'' from A.mass of the small strip is mx*dx.moment of inertia of the small strip about A IS m*x*dx*x*x.on integrating we get moment of inetia about A as 4*m*L*L*L*L.ABOUT MID POINT OF AB.consider a strip of length ''dx'' at a distance of x from mid point P.mass of it is m*(L-x)*dx.moment of inertia of half of the rod about P is m*(L-x)*dx*x*x.on integration we get moment of inertia of half of the rod.similarly do for the other half.adding them we get the answer.
Deduce an expression for the electric potential because of an electric dipole at any point on its axis. Mention one contrasting feature of electric potential of a dipole at a point
what is like and unlike forces
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An equilateral triangle is inscribed in a circle of radius 2 cm if P lies inside the triangle then the minimum sum of distances of P from the sides of the triangle is? Ans
Frequency:- The number of vibration done per second by an oscillation body is known its frequency. It is denoted by V. The S.I unit is Hz.
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