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Give the formula for the average access time experienced by the processor in a system with 2 levels of caches.
Ans: Formula is for the average access time experienced by the processor in a
system having two levels of caches is described follow:
tave = h1C1+(1-h1)h2C2+(1-h1)(1-h2)M
h1=> hit rate in the L1 cache
h2= > hit rate in the L2 cache
M=> it's time to access information in the main memory
C1=> it's for time to access information in the L1 cache
C2=> it's for time to access information in the L1 cache
Explain Hit and Miss?
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