Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
One of the simplest circuits is the asynchronous or ' ripple' counter. Below is shown the circuit diagram of a simple 3 stage ripple counter.
The operation of this circuit is based on the fact that the truth table for the JK flip flop is only valid if the clock waveform is falling, i.e. 1->0. Assume the outputs are all zero, the flip flops will not change until the clock on each flip flop falls. The clock in waveform has just fallen ,since the JKa inputs are logic '1' the device will toggle and the output will invert i.e. Qa=1. Flip flop B will not change because the clock waveform on B has risen (0->1) and these devices only functions on a falling edge. The clock in waveform has fallen again, so Qa toggles again (i.e. Qa =0), this has just produced a falling clock on JKb and Qb toggles (i.e. Qab=1) .The device has just counted from 000-> 001->010.
The circuit is called a ripple counter because the clock pulse is slowly rippling through the JK's, hence asynchronous (Not at the same time!) .The limitations of the asynchronous counter is the speed of operation. A rough formula for the maximum speed is when the clock changes before the output changes i.e. F = 1 / n x propagation delay where n = number of stages, propagation delay of one JK
A better technique is to use a synchronous design where all the JK are clocked together so the maximum frequency is only limited by the propagation delay of 1 JK.
The circuit appears to be complex in design, however it is easily realised by using state diagrams. The maximum frequency of operation is again roughly calculated by considering the frequency at which the output just changes before the clock in changes. F = 1/ Propagation delay
Q. A source of impedance ¯ Z S = R S = 100 has an open-circuit voltage v S (t) = 12.5 cos ωot and drives a 75- transmission line terminated with a 75- load. Find the current
what ''s part of dcmotor or dc generator
Branch Operations Normally the program executes in a sequence. The contents of the program counter register are incremented by one during the execution of current instr
Q. In a GLC parallel circuit excited by a current source i(t), for G = 0.5S, L = 3H, and C = 0.5 F, determine i(t) if the inductor current iL(t) = 12e -0.5t .
Q. Design a water supply scheme for a station, adopting the following data - a) Source of water - River flow at a distance of 1 km. b) Requirement of water - 1 lack gallons p
Q. Assuming the diode to obey I = IS (e V/0.026 -1), calculate the ratio V/I for an ideal diode with I S = 10 -13 A for the applied voltages of -2,-0.5, 0.3, 0.5, 0.7, 1.0, and
Q. Find the parameter values V T and I DSS for a p- channel MOSFET with i D = 0 when v GS ≤-3 V, and i D = 5 mA when v GS = v DS =-8V.You may neglect the effect of v DS on
Explain the different types of multivibrators ? Multivibrator is basically a two-stage amplifier with output of one supplied back to the input of the other . Multivibr
the p.u. reactance of a 25 MVA, 13.2 kV alternator 0.5 p.u. On a base of 50 MVA and 13.8 KV the p.u. value shall be
Suppose that the x rays are emitted from a focal spot isotropically. The photon flux is 3.28 x 10 6 photons mm -2 sec -1 at a distance of 0.75 m from the focal spot. What is the
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd