Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
One of the simplest circuits is the asynchronous or ' ripple' counter. Below is shown the circuit diagram of a simple 3 stage ripple counter.
The operation of this circuit is based on the fact that the truth table for the JK flip flop is only valid if the clock waveform is falling, i.e. 1->0. Assume the outputs are all zero, the flip flops will not change until the clock on each flip flop falls. The clock in waveform has just fallen ,since the JKa inputs are logic '1' the device will toggle and the output will invert i.e. Qa=1. Flip flop B will not change because the clock waveform on B has risen (0->1) and these devices only functions on a falling edge. The clock in waveform has fallen again, so Qa toggles again (i.e. Qa =0), this has just produced a falling clock on JKb and Qb toggles (i.e. Qab=1) .The device has just counted from 000-> 001->010.
The circuit is called a ripple counter because the clock pulse is slowly rippling through the JK's, hence asynchronous (Not at the same time!) .The limitations of the asynchronous counter is the speed of operation. A rough formula for the maximum speed is when the clock changes before the output changes i.e. F = 1 / n x propagation delay where n = number of stages, propagation delay of one JK
A better technique is to use a synchronous design where all the JK are clocked together so the maximum frequency is only limited by the propagation delay of 1 JK.
The circuit appears to be complex in design, however it is easily realised by using state diagrams. The maximum frequency of operation is again roughly calculated by considering the frequency at which the output just changes before the clock in changes. F = 1/ Propagation delay
Dielectric Heating Dielectric losses occur in insulating materials. These are same as hysteresis losses in magnetic materials. When an alternating electric field is a
1. A 1 μm long and 100 μm 2 cross-sectional area silicon bar is doped with 10 16 /cm 3 phosphorous. Use the graph below to: a. Find the current at 300°K with 10 V applie
Q. Explain digital Storage Oscilloscope (DSO) with neat diagram, (b) Give the difference between analog and digital storage oscilloscope. Principle of operation : The availa
HOW TO PERFOM AUTO DIALLING USING GSM MODULE
define the physical significance of damping coefficient
Explain BIOS The IBM PC has in its ROM a collection of routines, each of which performs some particular function such as reading a character from keyboard, writing character to
a. Determine the circuit of three transistors dynamic RAM cell and define briefly read and write functions. b. Write short note on factors influencing choice of layer for wiring
1. Write a MATLAB program to generate and plot the signal x1(n) = [3 2 -2 0 7], n = 0,1,2,3,4.
Customer Service Management CRM involves several activities related to planning - both long terms and short terms, measurement and control, improvement and innovation of all a
Q. Consider the 4-bit R-2R ladder D/A converter with V ref =-10 V. Determine the analog output voltage when the binary input code is 1100. Also, find what reference voltage is to
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd