Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
One of the simplest circuits is the asynchronous or ' ripple' counter. Below is shown the circuit diagram of a simple 3 stage ripple counter.
The operation of this circuit is based on the fact that the truth table for the JK flip flop is only valid if the clock waveform is falling, i.e. 1->0. Assume the outputs are all zero, the flip flops will not change until the clock on each flip flop falls. The clock in waveform has just fallen ,since the JKa inputs are logic '1' the device will toggle and the output will invert i.e. Qa=1. Flip flop B will not change because the clock waveform on B has risen (0->1) and these devices only functions on a falling edge. The clock in waveform has fallen again, so Qa toggles again (i.e. Qa =0), this has just produced a falling clock on JKb and Qb toggles (i.e. Qab=1) .The device has just counted from 000-> 001->010.
The circuit is called a ripple counter because the clock pulse is slowly rippling through the JK's, hence asynchronous (Not at the same time!) .The limitations of the asynchronous counter is the speed of operation. A rough formula for the maximum speed is when the clock changes before the output changes i.e. F = 1 / n x propagation delay where n = number of stages, propagation delay of one JK
A better technique is to use a synchronous design where all the JK are clocked together so the maximum frequency is only limited by the propagation delay of 1 JK.
The circuit appears to be complex in design, however it is easily realised by using state diagrams. The maximum frequency of operation is again roughly calculated by considering the frequency at which the output just changes before the clock in changes. F = 1/ Propagation delay
Explain Hall Effect. Hall Effect: If a current carrying conductor is placed in a magnetic field, a voltage is produced that acts in the perpendicular direction to the current
I needed a PLC and SCADA assignment just the program and it has to be done in simatic flexible and step 7 software!
Q. An n-channel enhancement MOSFET operates in the active region with very large V A , v GS = 6V, V = 4 V, and i = 1 mA. Calculate K.
Q. Assuming the diode to obey I = IS (e V/0.026 -1), calculate the ratio V/I for an ideal diode with I S = 10 -13 A for the applied voltages of -2,-0.5, 0.3, 0.5, 0.7, 1.0, and
Q. For the circuit shown in Figure, find the phasor values (with peak magnitudes) of ¯I, ¯V R , ¯V L , and ¯V C by using PSpice.
Parity flag - Registers If after any arithmetical or logical operation if number of the accumulator are even parity flag (P) is set otherwise reset.
Hi there i need help with design battery charger for electric scooter 24v battery. i have to design sechmatic diagram and PCB for it. using Altuim design software many thanks 006
A6KVA,100V/500V single-phase transformer has a secondary terminal voltage of 487.5 volts when loaded. determine the regulation of the transformer
With respect to serial communication define the baud rate. The rate of data transfer into serial data communication is denoted in bps. Bits per second (bps) are the rate of in
a) With the help of a neat and clean sketch illustrate the difference between relative and absolute motion measuring device. b) Discuss electromechanical methods for calculating
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd