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Assembly Language Programming
In this chapter we will discuss programming in assembly language and machine language. The difference in machine assembly and high level language has been already discussed in chapter1. In chapter 3 we have disused the completed instruction set of 8085. Although the aim of chapter 3 was to disuses various instructions but we have made small programs also to understand the working of some of the instructions. The reader are advised to read the chapter 3 before reading this chapter.
Q. Basic working of optical coupler? The optical coupler is suitable for frequencies in the low megahertz range. The photodiode type shown above can handle only small currents;
Q. Given the block diagram and the truth table of a demultiplexer, as shown in Figure, obtain its implementation.
Management Process of Balanced Score Card The BSC (Balanced Score Card) proposes four a new management processes which separately and in combination, contributes to linking lo
Semiconductor Equations The semiconductor equations that are relating these variables are shown below: Carrier density: n = n i exp (E FN - E i / KT) (1)
Question: a) What is the main difference between a latch and a flip flop? b) Draw the logic diagram of an SR-latch using only NAND gates. c) A positive edge triggered
State Kirchoff's Current Law Kirchoff's Current Law (KCL) describes at any junction in an electric circuit the total current flowing towards that junction is equivalent to th
Now that you have the input and output impedances you can design the matching networks. I will require either the Smith Charts showing how you calculated the matching components or
With a maximum excess delay of and a chip duration of , the multipath components fall in delay bins. This means that we experience leakage of energy between chips and the channel i
Q. Do as directed. a) Hexadecimal addition: 101 + ABC b) (43.25) 10-(89.75) 10 using 1's Complement c) Octal Subtraction 123-777 d) (123)6 + (435)6 = ( ? )6 e) ABC
Find the resistance of 800 m of copper cable of cross-sectional area 20 mm . Take the resistivity of copper as 0.02 Ωm.
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