Assembly language, Assembly Language

Assignment Help:

Assembly Language:

Inside the 8085, instructions are really stored like binary numbers, not a very good manner to look at them and very difficult to decipher. An assembler is a program that permits you to write instructions in, more or less, English form, much more simply read and understood, and after that converted or assembled into hex numbers and at last into binary numbers.

The program is written with a text editor (NOTEPAD or similar), saved like an ASM file, and then assembled by the assembler (TASM or MASM or similar) program. The end result is an OBJ file you download to the 8085. Here is an instance of the problem of adding 2 plus 2 :

mvi A,2; move 2 into the A register

mvi B,2; move 2 into the B register

add B; add reg. B to reg. A, store result in reg. A

The first line moves a 2 into a register A. The second line moves a 2 into a register B. it is all the data we require for the program. The third line adds up the accumulator with register B and holds the result back into the accumulator, destroying the 2 that were originally in it. The accumulator contains a 4 in it now and B still contains a 2 in it. In the program above all text after the ';' are treated as comments, and not executed. It is a very significant habit to acquire.

Assembly language follows some rules that we shall describe as they come up. With most of the instructions, especially those including data transfer, the instruction is first, followed by at least 1 space, after that the destination followed through a comma, and then the source. The destination is where the result of the instruction shall end up and the source is where the data is coming from.

Next we shall read a switch, and light an LED if the switch is pressed. This happens quite frequently in your lab experiments. Bit 0 of Port 0 shall be the switch. While the switch is closed or pressed, bit 0 will be a 1, and if the switch is open or not pressed, bit 0 will be a 0. Bit 0 of Port l is the LED. If bit 0 is a 0 the LED is off and if bit 0 is a 1, the LED shall be on. All the other bits of reg. A shall be ignored and assumed to be all 0's, for the sake of discussion

Start

IN         0          ; read Port 0 into reg. A

CMP    1          ;compare reg. A with the value 1

JNZ      start     ; jump to start if the comparison does not yield 0

OUT     1          ; send a 1 to Port 1, turning the LED on

JMP     start

 

The first line has something new. It's called as a label. In this case it is start:. A label is a manner of telling the assembler that this line has a name that may be referred to later to get back to it. All of the labels are followed by the symbol:, that tells the assembler that it is a label. In the first line we also read the switch by reading Port and putting it into the accumulator. Register. A is the only register that may read in/send out data using ports or perform compares. Therefore, we need not write 'A' in the command it's implied.


Related Discussions:- Assembly language

Or-logical instruction-microprocessor, OR: Logical OR: The OR instruction ...

OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar

Operating systems, what would be the typical pricing for helping out on Ope...

what would be the typical pricing for helping out on Operating systems 1 assignments at UCI

Zero flag, Zero flag: The next line compares the value in register. A ...

Zero flag: The next line compares the value in register. A with the value 1. If they are equivalent, the Zero flag is set (to 1). The next line then jumps to start: only if th

Any project ideas plz, can any one help me in my project by using assembly ...

can any one help me in my project by using assembly language

Solotuon, using 8086 assembly language that interchange upper four bits to ...

using 8086 assembly language that interchange upper four bits to lower four bits. assume that data store in byte memory and it written back to same location. and assume the data as

8088 associated with 8259 a-microprocessor, For an 8088 the 2 addresses lin...

For an 8088 the 2 addresses linked with an 8259A are normally consecutive, and the AO line is associated to the AO pin, but because there are just 8 data pins on the 8259A and the

Csc203 assembly language, I need to estimate the value of a definite integr...

I need to estimate the value of a definite integral using Riemann Sums and For our estimation let f(x) = x2 ,a=0, b=10 and n=5. Where a is the lower bound, b is the upper bound and

Interrupt system based on multiple 8259as-microprocessor, Interrupt System ...

Interrupt System Based on Multiple 8259As A multiple 8259A interrupt system is diagrammed in given figure in this figure data bus drivers are not indicated, but they could be i

Introduction to microprocessor, Introduction to Microprocessor: Micropr...

Introduction to Microprocessor: Microprocessor works like a CPU in a microcomputer. It's present as a single IC chip in a microcomputer. Microprocessor is the soul of the machi

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd