Assembly language, Assembly Language

Assignment Help:

Assembly Language:

Inside the 8085, instructions are really stored like binary numbers, not a very good manner to look at them and very difficult to decipher. An assembler is a program that permits you to write instructions in, more or less, English form, much more simply read and understood, and after that converted or assembled into hex numbers and at last into binary numbers.

The program is written with a text editor (NOTEPAD or similar), saved like an ASM file, and then assembled by the assembler (TASM or MASM or similar) program. The end result is an OBJ file you download to the 8085. Here is an instance of the problem of adding 2 plus 2 :

mvi A,2; move 2 into the A register

mvi B,2; move 2 into the B register

add B; add reg. B to reg. A, store result in reg. A

The first line moves a 2 into a register A. The second line moves a 2 into a register B. it is all the data we require for the program. The third line adds up the accumulator with register B and holds the result back into the accumulator, destroying the 2 that were originally in it. The accumulator contains a 4 in it now and B still contains a 2 in it. In the program above all text after the ';' are treated as comments, and not executed. It is a very significant habit to acquire.

Assembly language follows some rules that we shall describe as they come up. With most of the instructions, especially those including data transfer, the instruction is first, followed by at least 1 space, after that the destination followed through a comma, and then the source. The destination is where the result of the instruction shall end up and the source is where the data is coming from.

Next we shall read a switch, and light an LED if the switch is pressed. This happens quite frequently in your lab experiments. Bit 0 of Port 0 shall be the switch. While the switch is closed or pressed, bit 0 will be a 1, and if the switch is open or not pressed, bit 0 will be a 0. Bit 0 of Port l is the LED. If bit 0 is a 0 the LED is off and if bit 0 is a 1, the LED shall be on. All the other bits of reg. A shall be ignored and assumed to be all 0's, for the sake of discussion

Start

IN         0          ; read Port 0 into reg. A

CMP    1          ;compare reg. A with the value 1

JNZ      start     ; jump to start if the comparison does not yield 0

OUT     1          ; send a 1 to Port 1, turning the LED on

JMP     start

 

The first line has something new. It's called as a label. In this case it is start:. A label is a manner of telling the assembler that this line has a name that may be referred to later to get back to it. All of the labels are followed by the symbol:, that tells the assembler that it is a label. In the first line we also read the switch by reading Port and putting it into the accumulator. Register. A is the only register that may read in/send out data using ports or perform compares. Therefore, we need not write 'A' in the command it's implied.


Related Discussions:- Assembly language

Aad-arithmetic instruction-microprocessor, AAD: ASCII Adjust for Division ...

AAD: ASCII Adjust for Division though the names of these 2 instructions (AAM and AAD) seem to be same, there is many difference between their functions. The AAD instruction conver

2 homework assignements, I have two homework assignments due in 10 hours fo...

I have two homework assignments due in 10 hours for the x86 processor assembly language

Rcr-rcl-logic instruction-microprocessor, RCR: Rotate Right through Carry:...

RCR: Rotate Right through Carry:- This instruction rotates the contents  bit-wise of the destination operand right by the specified count through carry flag (CF). For each operati

Implement an assembly language program, A good starting point for your prog...

A good starting point for your program is the toupper.asm program shown in class. It already queries the user for input and sets up a loop that looks at each character of the input

Intel''s 8237 dma controller-microprocessor, Intel's 8237 DMA controller : ...

Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)

PIC lights on, errorlevel -302 ;prevents error code for this...

errorlevel -302 ;prevents error code for this chipset __config 0x373A ;chip config PIC spec page 146 processor 16F877A ;chipset reset code

Program, Write an application that does the following: (1) fill an array wi...

Write an application that does the following: (1) fill an array with 50 random integers; (2) loop through the array, displaying each value, and count the number of negative values;

Lods-stos-string manipulating instruction-microprocessor, LODS : Load Stri...

LODS : Load String Byte or String Word:- The LODS instruction loads AL/AX register by the content of a string pointed to by DS:SI register pair. The SI is automatically modifie

Avr, how to code

how to code

Lab Assignment, 1) Write an 80x86 assembly language program in EXE file for...

1) Write an 80x86 assembly language program in EXE file format to do the following tasks: a) Open and read the contents of a file into memory (use at least 1 kB). b) Sort the li

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd