Assembly language, Assembly Language

Assignment Help:

Assembly Language:

Inside the 8085, instructions are really stored like binary numbers, not a very good manner to look at them and very difficult to decipher. An assembler is a program that permits you to write instructions in, more or less, English form, much more simply read and understood, and after that converted or assembled into hex numbers and at last into binary numbers.

The program is written with a text editor (NOTEPAD or similar), saved like an ASM file, and then assembled by the assembler (TASM or MASM or similar) program. The end result is an OBJ file you download to the 8085. Here is an instance of the problem of adding 2 plus 2 :

mvi A,2; move 2 into the A register

mvi B,2; move 2 into the B register

add B; add reg. B to reg. A, store result in reg. A

The first line moves a 2 into a register A. The second line moves a 2 into a register B. it is all the data we require for the program. The third line adds up the accumulator with register B and holds the result back into the accumulator, destroying the 2 that were originally in it. The accumulator contains a 4 in it now and B still contains a 2 in it. In the program above all text after the ';' are treated as comments, and not executed. It is a very significant habit to acquire.

Assembly language follows some rules that we shall describe as they come up. With most of the instructions, especially those including data transfer, the instruction is first, followed by at least 1 space, after that the destination followed through a comma, and then the source. The destination is where the result of the instruction shall end up and the source is where the data is coming from.

Next we shall read a switch, and light an LED if the switch is pressed. This happens quite frequently in your lab experiments. Bit 0 of Port 0 shall be the switch. While the switch is closed or pressed, bit 0 will be a 1, and if the switch is open or not pressed, bit 0 will be a 0. Bit 0 of Port l is the LED. If bit 0 is a 0 the LED is off and if bit 0 is a 1, the LED shall be on. All the other bits of reg. A shall be ignored and assumed to be all 0's, for the sake of discussion

Start

IN         0          ; read Port 0 into reg. A

CMP    1          ;compare reg. A with the value 1

JNZ      start     ; jump to start if the comparison does not yield 0

OUT     1          ; send a 1 to Port 1, turning the LED on

JMP     start

 

The first line has something new. It's called as a label. In this case it is start:. A label is a manner of telling the assembler that this line has a name that may be referred to later to get back to it. All of the labels are followed by the symbol:, that tells the assembler that it is a label. In the first line we also read the switch by reading Port and putting it into the accumulator. Register. A is the only register that may read in/send out data using ports or perform compares. Therefore, we need not write 'A' in the command it's implied.


Related Discussions:- Assembly language

Program of generate a random number, This is a short program to practice as...

This is a short program to practice assembly language loops and if/else statements. You will use various jump commands and the cmp instruction. The program will generate a random

Sub-arithmetic instruction-microprocessor, SUB: Subtract :- The subtract in...

SUB: Subtract :- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory locati

8086 program, program to arrange a given set of numbers in descending order...

program to arrange a given set of numbers in descending order

Memory segmentation-microprocessor, Memory Segmentation : The  memory ...

Memory Segmentation : The  memory in an 8086/8088  based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n

Write a mips assembly language program, Write a MIPS/SPIM assembly language...

Write a MIPS/SPIM assembly language program that prints the smallest and largest values found in a non-empty table of N word-sized integers. The address of the first entry in your

Calculator, how to add 111 and 333 in assembly language

how to add 111 and 333 in assembly language

Intel 8259 interrupt controller-microprocessor, Intel 8259 interrupt contro...

Intel 8259 interrupt controller :  The 8088 processor has only two interrupt control inputs, and interrupt request (INTR) and non mask able interrupt (NMI). NMI are interrupts t

8086, Ask(2) Write a program to mask bits D3D2D1D0 and to set bits D5D4 and...

Ask(2) Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to invert bits D7D6 of the AX register question #Minimum 100 words accepted#

Assignment, You have to write a subroutine (assembly language code using NA...

You have to write a subroutine (assembly language code using NASM) for the following equation.

Signal descriptions of 8086-microprocessor, Signal descriptions of 8086 : ...

Signal descriptions of 8086 : described below are common for the maximum andminimum mode bothdata lines AD15 -AD0: These are the time multiplexed andmemory I/O address. Addre

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd