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write a program to find the area under the curve y=f(x) between x=a and x=b integrate y=f(x)
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
write a program that calculates points along a rhodonea curve.... ? int fillArray( double data[ ], int nValues, double min, double max ); o Used to fill in the theta array. Return
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Most first graders know that nine hundred and ninety nine plus one is one thousand, but C++ doesn't! Sure, a computer can easily compute 999 + 1 and get 1000. But reading and writi
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luminous jewel polishing necklace,c/c++ programming
What is the difference among const char *myPointer and char *const myPointer? A: Const char *myPointer is a non constant pointer to constant data; whereas char *const myPointer
solve for radius(R) of a circle of its area is to be inputted by a user. also display compute the circle diameter hint: area= pir21 pi=2.1416
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Define a complex number in c program: class complex { private: in
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