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write a program to find the area under thecurve y=f(x)between x=a and x=b, integrate y=f(x) between the limits of a and b. the area under a curve between two points can be found by doing a definite integral beteen the two points..
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
What is the name of the services you have chosen? What do they do? What is the name of the publisher? Provide details if you are developing your own service(s). There are variou
how do I use constructors in java and how do I apply them
It helps to resolve naming conflicts when different packages have classes with the same names. This also helps you prepare files within your project. As define : java.io package
we can insert elements at rear and remove at front bt my question is that how we insert at front in circular queue
RMI uses a layered architecture; every of the layers could be increased or replaced without affecting the rest of the system. The details of layers can be summarised as follows:
Are you real? I dont want to get help from a computer
Ask questionWrite a program BruteForceSearch that uses the brute-force approach given above and compare its running time on your computer with that of Binary Search for largeW.txt
Students will design, develop, test and document a Java application that reads data from an input file, processes the data, and then writes the processed data to an output file. CM
Get info from website using javascript Project Description: I need to extract the text from all the available (red, blue) seats of all the events on this site without getting
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