Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
#Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y =f(x) between the limits of a and b.
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
write a c++ program, that finds the minimum total number of shelves, including the initial one, required for this loading process.
Mixed Mode Expressions and Implicit type Conversions A mixed mode expression is one in which the operands are not of the similar type. In this case, the operands are converted
Each function has its own stack frame between %fp and %sp. Let Caller calls Callee. Then Caller's %sp becomes callee's %fp, and callee's %sp set to be a new value (a smaller one be
Type Casting Implicit type conversions, as allowed by the language, can lead to errors creeping in the program if care is not taken. Thus, explicit type conversions may be used
reocord of a student and a function ctotal to calculate the marks of any three subject by using ctotal() function
how to call the value
#include stdio.h> #include conio.h> #include string.h> void del(char[],char *); main() { char str[30],ch,*pp; clrscr(); p
compose a C program to solve the equation z2=(p1/Pg)+(v1^2/2g)+z1 p1=100kpa,v1=2m/s z1=3m P=1000kg/m^3 define g=9.81
Homework – Chapter 5 – Bowling Scores 33. Write a complete C++ program to do the following: The main program reads in and prints three bowling scores, score1, score2, and score
A: Method of passing arguments to a function that takes parameter of type reference. for instance: void swap( int & x, int &amp; y ) { int temp = x; x =
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd