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write a program to find area of curve y=f(x) between x and x=b,integrate between the limits a and b using c
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
how to define the structures
Scope Rules and Storage Classes The storage class verifies the life of a variable in terms of its duration or its scope. There are four storage classes : automatic static
If an array holds integer, each of which is four bytes long, how many bytes from the base location of the array is the location of the fifth element?
answer for this program
Byteland county is very famous for luminous jewels. Luminous jewels are used in making beautiful necklaces. A necklace consists of various luminous jewels of particular colour. Nec
Define the Classification of Operators in C Language? Depending on the function performed the operator can be classified as 1. Arithmetic Operator 2. Logical Operator 3. Inc
it is a class enclosed in the scope of another class. For illustration: // Example: Nested class // class OuterClass { class NestedClass { // ... }; // .
A: No. If they're utilized properly, they increase encapsulation. You frequently require splitting a class in half while the two halves will have distinct numbers of instances o
When declaring a variable of data type pointer, use the * in front of the variable name. These variables hold a memory location (like B45CDF), not an actual value like 30 or A:
Test scores solution help. Three member variables
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