Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
write a program to find area of curve y=f(x) between x and x=b,integrate between the limits a and b using c
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
explain thee structure of c program
C Coding to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can be found
compose a C program to solve the equation z2=(p1/Pg)+(v1^2/2g)+z1 p1=100kpa,v1=2m/s z1=3m P=1000kg/m^3 define g=9.81
Pointer Arithmetic We can manipulate the pointers too. We can perform operations such as addition, subtraction, increment and decrement etc.,. As the pointer variables have add
my program does not run more than 9 iterations when ever i want to iterate more than 100 iterations. what is the reason and how to tackle?
Defines the entry point for the console application. // #include "stdafx.h" #include #include #include"conio.h" using namespace std; double Determinant(double a[][3],int forde
C Program for FUNCTION OF COUNT THE INTEREST float si(float,float,float); void main() { float p=0,r=0,n=0,k=0; clrscr(); printf("E
C Program for FUNCTION OF COPY ONE STRING IN OTHER STRING #include stdio.h> #include conio.h> int copy(char a[],char b[]); void main() { char a[100],b[
decleration
Simple program of c++: int main() { int bushels; float dollars, rate; cout cin >> dollars; cout
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd