Approximating solutions to equations newtons method, Mathematics

Assignment Help:

Approximating solutions to equations : In this section we will look at a method for approximating solutions to equations. We all know that equations have to be solved on occasion and actually we've solved out quite a few equations by ourselves to this point.  In all the instances we've looked at to this instance we were capable to in fact find the solutions, however it's not always probable to do that exactly and/or do the work by hand.

That is where this application comes into play.  Therefore, let's see what this application is all about.

1141_Newton’s Method.png

Let's assume that we desire to approximate the solution to f (x) = 0 and let's also assume that we have somehow found an initial approximation to this solution say, x0. This initial approximation is perhaps not all that good and therefore we'd like to discover a better approximation. It is easy enough to do.  Firstly we will get the tangent line to f ( x )at x0.

y = f ( x0 ) + f ′ ( x0 ) ( x - x0 )

Now, take a look at the graph below.

The blue line (if you're reading this in color anyway...) is the tangent line at x0. We can illustrate that this line will cross the x-axis much closer to the actual solution to the equation than x0 does.  Let's call this point where the tangent at x0 crosses the x-axis x1 and we'll utilizes this point as our new approximation to the solution.

Therefore, how do we determine this point? Well we know it's coordinates, ( x1 ,0) , and we know that it's on the tangent line therefore plug this point into the tangent line & solve out for x1 as follows,

0 = f ( x0 ) + f ′ ( x0 ) ( x1 - x0 )

x - x0 = -  f (x0 ) /f ′ ( x0 )

x1 = x0  - (f ( x0 ) /f ′ ( x0 ))

Therefore, we can determine the new approximation provided the derivative isn't zero at the original approximation.

Now we repeat the whole procedure to determine an even better approximation. We build up the tangent line to f ( x ) at x1 and utilizes its root, that we'll call x2, as a new approximation to the actual solution.  If we do it we will arrive at the given formula.

                  x2= x1 - (f ( x1 ) /f ′ ( x1 ))

This point is also illustrated on the graph above and we can illustrated from this graph that if we continue following this procedure will get a sequence of numbers which are getting very close the real solution. This procedure is called Newton's Method.


Related Discussions:- Approximating solutions to equations newtons method

Solid mensuration., assuming that the earth''s sphere with a radius of 6400...

assuming that the earth''s sphere with a radius of 6400 km.. find the distance along a 3 degree arc at the equator of the earth''s surface?

How much is invested at 8% if the total amount of interest, Kevin invested ...

Kevin invested $4,000 in an account which earns 6% interest per year and $x in a different account that earns 8% interest per year. How much is invested at 8% if the total amount o

Quotient rule (f/g)'' = (f''g - fg'')/g2, Quotient Rule (f/g)' = (f'g - ...

Quotient Rule (f/g)' = (f'g - fg')/g 2 Here, we can do this by using the definition of the derivative or along with Logarithmic Definition. Proof Here we do the pr

Factoring polynomials, Factoring polynomials is probably the most important...

Factoring polynomials is probably the most important topic. We already learn factor of polynomial .If you can't factor the polynomial then you won't be able to even start the probl

Find the generating function, Find the generating function for the number o...

Find the generating function for the number of r-combinations of {3.a, 5.b, 2.c}          Ans:  Terms sequence is given as r-combinations of {3.a, 5.b, 2.c}. This can be writte

Solid Mensuration, The two sides of a triangle are 17cm and 28cm long, and ...

The two sides of a triangle are 17cm and 28cm long, and the length of the median drawn to the third side is equal to 19.5 cm. What is the distance from an endpoint of the median to

Surds and logarithms, what are these all about and could i have some exampl...

what are these all about and could i have some examples of them please

Shares and dividend, A man invests rs.10400 in 6%shares at rs.104 and rs.11...

A man invests rs.10400 in 6%shares at rs.104 and rs.11440 in 10.4% shares at rs.143.How much income would he get in all??

Leptokurtic-measure of central tendency, Leptokurtic a) A frequency di...

Leptokurtic a) A frequency distribution which is lepkurtic has normally a higher peak than that of the general distribution. The coefficient of kurtosis while determined will

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd