Approximating solutions to equations newtons method, Mathematics

Assignment Help:

Approximating solutions to equations : In this section we will look at a method for approximating solutions to equations. We all know that equations have to be solved on occasion and actually we've solved out quite a few equations by ourselves to this point.  In all the instances we've looked at to this instance we were capable to in fact find the solutions, however it's not always probable to do that exactly and/or do the work by hand.

That is where this application comes into play.  Therefore, let's see what this application is all about.

1141_Newton’s Method.png

Let's assume that we desire to approximate the solution to f (x) = 0 and let's also assume that we have somehow found an initial approximation to this solution say, x0. This initial approximation is perhaps not all that good and therefore we'd like to discover a better approximation. It is easy enough to do.  Firstly we will get the tangent line to f ( x )at x0.

y = f ( x0 ) + f ′ ( x0 ) ( x - x0 )

Now, take a look at the graph below.

The blue line (if you're reading this in color anyway...) is the tangent line at x0. We can illustrate that this line will cross the x-axis much closer to the actual solution to the equation than x0 does.  Let's call this point where the tangent at x0 crosses the x-axis x1 and we'll utilizes this point as our new approximation to the solution.

Therefore, how do we determine this point? Well we know it's coordinates, ( x1 ,0) , and we know that it's on the tangent line therefore plug this point into the tangent line & solve out for x1 as follows,

0 = f ( x0 ) + f ′ ( x0 ) ( x1 - x0 )

x - x0 = -  f (x0 ) /f ′ ( x0 )

x1 = x0  - (f ( x0 ) /f ′ ( x0 ))

Therefore, we can determine the new approximation provided the derivative isn't zero at the original approximation.

Now we repeat the whole procedure to determine an even better approximation. We build up the tangent line to f ( x ) at x1 and utilizes its root, that we'll call x2, as a new approximation to the actual solution.  If we do it we will arrive at the given formula.

                  x2= x1 - (f ( x1 ) /f ′ ( x1 ))

This point is also illustrated on the graph above and we can illustrated from this graph that if we continue following this procedure will get a sequence of numbers which are getting very close the real solution. This procedure is called Newton's Method.


Related Discussions:- Approximating solutions to equations newtons method

Prove that ad x af=ae x ab, ABCD is a rectangle. Δ ADE and Δ ABF are two tr...

ABCD is a rectangle. Δ ADE and Δ ABF are two triangles such that ∠E=∠F as shown in the figure. Prove that AD x AF=AE x AB. Ans:    Consider Δ ADE and Δ ABF ∠D = ∠B

probability that they are both the same color, Consider two bags, A and B,...

Consider two bags, A and B, with the following contents a)    A single marble is drawn from each bag. What is the probability of getting a white marble out of Bag A and a red marb

Find out all the critical points and derivation, Find out all the critical ...

Find out all the critical points for the function. Solution Following is the derivative for this function. Now, this looks unpleasant, though along with a little fa

Solve following 4e1+3 x - 9e5-2 x = 0 logarithms, Solve following 4e 1+3 x...

Solve following 4e 1+3 x - 9e 5-2 x  = 0 . Solution Here the first step is to get one exponential on every side & then we'll divide both sides by one of them (that doesn'

What is the probability of getting a royal flush, Q. What is the probabilit...

Q. What is the probability of getting a Royal Flush? Ans. Five cards are picked from a standard deck of 52 cards. How many different hands of five cards are possible? What

Integrals involving roots - integration techniques, Integrals Involving Roo...

Integrals Involving Roots - Integration Techniques In this part we're going to look at an integration method that can be helpful for some integrals with roots in them. We hav

Show that positive integers is divisible by 6, Show that the product of 3 c...

Show that the product of 3 consecutive positive integers is divisible by 6. Ans: n,n+1,n+2 be three consecutive positive integers We know that n is of the form 3q, 3q +1

Write down the first few terms of the sequences, Write down the first few t...

Write down the first few terms of each of the subsequent sequences. 1. {n+1 / n 2 } ∞ n=1 2. {(-1)n+1 / 2n} ∞ n=0 3. {bn} ∞ n=1, where bn = nth digit of ? So

Statistics, How many 4 digit numbers can be formed using the numbers: 1 – 7...

How many 4 digit numbers can be formed using the numbers: 1 – 7. Repeated numbers CAN NOT be used

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd