Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
write a program to find the area under the curve y=f(x) between x=a and y=b integrate y=f(x) between the limits of a and b. the area under a curve between two points can be found by doing a definite integral between a to points.
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
What is guard bits? Guard bits are extra bits which are produced while the intermediate steps to yield maximum accuracy in the final results.
What happens when HLT instruction is implemented in processor? Ans) The Micro Processor go into the Halt-State and the buses are tri-stated.
Why Build and fix model is considered as ad-hoc software development model?
Q. Program size for different Instruction Set Approaches? Assumptions: Complex Instruction is: Add C, A, B having 16 bit addresses and 8 bit data operands All opera
Define Algebraic method for Simplification of the Boolean Expressions This method is depend on the by knowledge of the Boolean algebra. Expression can be making simpler by usin
Q. Explain Indirect Cycle in control unit? Once an instruction is fetched the subsequent step is to fetch the operands. The instruction may have indirect and direct addressing
Q. FORALL Statement in fortran? The FORALL statement permits for more common assignments to sections of an array. A FORALL statement has general form. FORALL ( triplet, ..
How is EISA bus different from ISA bus? Extended Industry Standard Architecture (EISA) is a 32 bit modification to ISA bus. As computers became larger and had wider data buses,
What is a deadlock? A deadlock is a situation that can increase when two units, A and B use a shared resource. Assume that unit B cannot complete its task unless unit A complet
Mainframe computer Mainframe computers are very large, often can fill an entire room. They can store a large amount of information, can execute many tasks at the same time, can
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd