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At what angle should a body be projected with a given velocity 24m/s just to pass over the obstacle 14m high at a given distance of 24m.
Solution: 14=24xtan(θ)-(g*)(242)/(2*242cos2( θ ))
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TIME OF FLIGHT: "It is the total time for which the projectile remains in air". As, the body goes up and comes back to similar level, so it does not cover vertical distance,
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