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i) The width of the sorting + merging circuit is equivalent to maximum number of devices needed in a phase is O(n/2). As in the above diagram maximum number of devices for a given phase is 4 that is 8/2 or n/2.
ii) The circuit comprises two sorting circuits for sorting sequences of length n/2 and afterwards one merging circuit for merging of two sorted sub sequences (see phase 4th in above figure). Let functions Tm and Ts signify the time complexity of merging and sorting in terms of its depth.
The Ts can be calculated as follows:
Ts (n) =Ts (n/2) + Tm (n/2)
Ts (n) =Ts (n/2) + log (n/2),
Therefore, Ts (n) is equal to O (log2 n).
Figure: Sorting + Merging Circuit
The 2's complement of the number 1101110 is ? Ans. 1's complement of 1101110 is = 0010001 ans hence 2's complement of 1101110 is = 0010001 + 1 = 0010010.
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