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Q. Analog Computers?
Although not used as much as the digital computer (which nowadays forms the basic tool for numerical analysis and the solution of algebraic as well as differential equations), the analog computer still retains some significant advantages over the digital computer. A physical system can be represented by a set of differential equations which can be modeled on an analog computer that uses continuously varying voltages to represent system variables. The differential equation is solved by the computer, whereas the modeled quantities are readily varied by adjusting passive components on the computer. The mathematical functions (integration, addition, scaling, and inversion) are provided by op amps.
The analog computer components are shown in Figure. Let the ordinary differential equation to be solved be
The simulation of the solution is accomplished by the connection diagram of Figure 5.4.19. Time scaling is done by redefining t as t = ατ , in which case the differential equation [Equation] becomes
The coefficients may simply be scaled by the appropriate factors to change the solution time of the analog computer. For example, if α = 20, then t = 20 s corresponds to τ = 1 s, and thus the solution time may be reduced.
HLT Halt Instruction The microprocessor halts the execution of the program and enters into the wait state the address and data bus are placed in the high impedance st
Draw the implementation of time-invariant system A linear time-invariant system is described by the difference equation: y[n] = 2x[n] - 3x[n - 1] + 2x[n - 2] Draw the i
Consider a GLC parallel circuit excited by i(t) = Ie st in the time domain. Assume no initial inductive current or capacitive voltage at t = 0. Draw the transformed network in the
Circuits, which provide sinusoidal waveforms, are but useful in themselves and form the basis of many other circuits, such as square and triangular waveform generators, and clocks.
Reverse bias Reverse biased generally refers to how a diode is employed in a circuit. If a diode is reverse biased, the voltage at the cathode is gets higher than that at the
Q. In an AM transmitter that transmits a total power of 1 kW, the unmodulated carrier power is 850 W. Compute the required value of (S i /N i )AM at a receiver, if (S 0 /N 0 )AM
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