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An 8086 interrupt can take placedue to the following reasons:
1. Hardware interrupts caused by some external hardware device.
2. Software interrupts that can be invoked with the help of INT instruction.
3. Conditional interrupts that are mainly caused because of some error condition produced in 8086 by the execution of an instruction.
When an interrupt can be serviced by a procedure it is known as the Interrupt Service Routine (ISR). Starting addresses of the interrupt service routines are present in first 1K addresses of the memory. This table is known as the interrupt vector table.
Q. Explain Logical shifts with example? Logical shifts LOGICAL SHIFT LEFT and LOGICAL SHIFT RIGHT insert zeros to end bit position and other bits of a word are shifted left or
DEFINE FILE ORGANISATION
Parallel Computers In India, the design and development of parallel computers in progress in the early 80?s. The Indian Government recognized the Centre for Development of Adva
The reason is, LINQ is used with C# or other programming languages, which needs all the variables to be declared first. From clause of LINQ query just describes the range or condit
Q. Define syntax of MPI_Scatter function? MPI_Scatter(Sendaddr, Scount, Sdatatype, Receiveaddr, Rcount, Rdatatype, Rank, Comm): 'Using this function process with rank' ran
The main benefits of CD-ROMs are: These are removable disks, thus they are suitable for archival storage mass replication is cheap and fast large storage capacity
How authoring packages supports scripting language Many authoring packages support a scripting language to allow for even more sophisticated applications to be produced. Scrip
Q. Develop a Menu driven program with following menu: a. Binary to Decimal b. Binary to Octal c. Binary to Hexadecimal d. Exit (Put proper validation for input
The outcomes of analysis of Amdahl's law are: 1) To optimize the performance of parallel computers, modified compilers need to be developed which should aim to decrease the numb
Define Overflow. An overflow is a problem in digital computer due to the width of registers is finite. A result that contains n+ 1 bit cannot be accommodated in a register wit
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