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An 8086 interrupt can take placedue to the following reasons:
1. Hardware interrupts caused by some external hardware device.
2. Software interrupts that can be invoked with the help of INT instruction.
3. Conditional interrupts that are mainly caused because of some error condition produced in 8086 by the execution of an instruction.
When an interrupt can be serviced by a procedure it is known as the Interrupt Service Routine (ISR). Starting addresses of the interrupt service routines are present in first 1K addresses of the memory. This table is known as the interrupt vector table.
It depends on our requirement. When we are needed an integer to be stored in 1 byte (means less than or equal to 255) we use short int, for 2 bytes we use int, for 8 bytes we use l
Convert (177.25) 10 to octal Ans. 177.25) 10 = ( ) 8 Firstly we take integer part Hence (177) 10 = (261) 8 Now as 0.25 x 8 = 2.00 and 0.00 x 8 = 0 Therefor
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Can someone provide me a scehmatic diagram of RS232C with explanation?
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