Amperes circuital law, Electrical Engineering

Assignment Help:

Amperes Circuital Law

The    observation    that    magnetic    field strength varied with distance from the wire led to the following statement:

'If  the  magnetic  field  H  is  integrated along a closed path, the result is equal to the current enclosed'.

This is the basis with which we can relate the strength of a magnetic field to the current producing it. It is an extremely important statement. Note that only the component of H that lies along the path is to be considered, so the Law may be stated mathematically as:


∫ H     dl     ∑ I


where the  vector  dot  product  is used  (= H.dl.cos  ).  Note that  both H  and  dl are vectors.  The  direction  of  H  around  a current carrying conductor is given by the 'right hand corkscrew rule' , attributed to Maxwell.Ampere's  Circuital  Law  applies  for  any path chosen for the integration. If the chosen path does not enclose any current, the result of the integration will be zero.

To apply this law to the case of a long, thin current carrying conductor, it is convenient to choose a circular path of constant radius centred on the wire. Since any path could be chosen, the circular path is chosen simply to make the integration easy, H being  both constant  and  tangential  for  a given radius from the wire.

Hence

∫ H     dl     ∑ I

H.2  r = I
 
H  = I/2  r


For I1  = I2  =1 amp and r = 1 metre, the force/metre   in  a   vacuum  =   2   x  10-7
Newtons   by  definition  of  the  ampere. Hence    =    0 = 4   x 10-7

Had Ampere been able to conduct his experiments involving the force between current carrying conductors in materials other than air, he would have found that the material involved also affected the force. This can be taken into account by introducing a property called the 'relative magnetic permeability' of a material and is given the symbol   r.

 

Different materials have different values of . These are related to that for a vacuum (or   for practical  purposes, air)  by introducing  the   concept  of         relative permeability  r  which expresses  for the material relative to that for a vacuum, i.e.

=   0   r.

 

Finally, the quantity .H is defined as the flux density B (i.e. the number of flux lines/m2) so the flux density B is:

B  =    0   rH

so    the    force    on    a    current    carrying conductor in a magnetic field H  may be expressed in terms of the resulting flux density to be:

 

force/metre = B. I2

or

force = B.I.L

 

1.    when  we  draw  flux  lines  on  a diagram, the density of those lines (number/m2)  depicts  the  product 0   rH rather than just H.

2.  flux lines are always continuous.They do not start or stop in space -.i.e. they are always loops, even though they may not always be shown as such in some diagrams

 

 

 


Related Discussions:- Amperes circuital law

Can you explain about multiple poles, Q. Can you explain about Multiple Pol...

Q. Can you explain about Multiple Poles? Let us consider that F 1 (s) has all simple poles except, say, at s = p 1 which has a multiplicity m. Then one can write When

Discuss the disadvantages of an rc coupled amplifier, Q. Discuss the disadv...

Q. Discuss the disadvantages of an RC coupled amplifier? RC coupled amplifiers have a few disadvantages. The resistors use dc power and so the amplifier has low efficiency. The

Averaged power dissipated in the load, (a) Consider the following transmiss...

(a) Consider the following transmission line with the reactance X1 placed across the input. It is being driven with a frequency ω such that the length of the line is λ/4. What v

Scr, What is finger voltage in a scr?

What is finger voltage in a scr?

Assignment, Hi, I got assignment to design a power electronic system Design...

Hi, I got assignment to design a power electronic system Design the circuit and select the appropriate components for that circuit to fulfil the requirements of the device. Regards

Compute the effective armature, For a 45-kVA, three-phase, wye-connected, 2...

For a 45-kVA, three-phase, wye-connected, 220- V synchronous machine at rated armature current, the short-circuit load loss (total for three phases) is 1.80 kWat a temperature of 2

Tunneling effect, what is tunneling effect ? With calculation.

what is tunneling effect ? With calculation.

amp circuit , Refer to the op amp circuit shown below. Let R 1 = ...

Refer to the op amp circuit shown below. Let R 1 = 140 k_, R 2 = 10 k_, R 3 = 10 k_, R 4 = 20 k_, RL = 10 k_. Assume the op amp is ideal. Find the equation relating the

Semiconductor, what are the most 4 types of doping techinques in semiconduc...

what are the most 4 types of doping techinques in semiconductors

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd