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Step-1: For the current node, verify whether it contain a left child. If it has, then go to step-2 or else go to step-3
Step-2: Repeat step-1 for left child
Step-3: Visit (that means printing the node in our case) the current node
Step-4: For the current node verify whether it contain a right child. If it contain, then go to step-5
Step-5: Repeat step-1 for right child
Figure: A binary tree
The preoreder & postorder traversals are similar to that of a general binary tree. The general thing we have seen in all of these tree traversals is that the traversal mechanism is recursive inherently in nature.
#questionalgorithm for implementing multiple\e queues in a single dimensional array
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Now, consider a function that calculates partial sum of an integer n. int psum(int n) { int i, partial_sum; partial_sum = 0; /* L
We might sometimes seek a tradeoff among space & time complexity. For instance, we may have to select a data structure which requires a lot of storage to reduce the computation tim
for(int i = 0; i for (int j = n - 1; j >= i ; j--){ System.out.println(i+ " " + j);
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