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Step-1: For the current node, verify whether it contain a left child. If it has, then go to step-2 or else go to step-3
Step-2: Repeat step-1 for left child
Step-3: Visit (that means printing the node in our case) the current node
Step-4: For the current node verify whether it contain a right child. If it contain, then go to step-5
Step-5: Repeat step-1 for right child
Figure: A binary tree
The preoreder & postorder traversals are similar to that of a general binary tree. The general thing we have seen in all of these tree traversals is that the traversal mechanism is recursive inherently in nature.
Q. Assume that we have separated n elements in to m sorted lists. Explain how to generate a single sorted list of all n elements in time O (n log m )?
24 56 47 35 10 90 82 31
D elete a specific Node from Double Linked List as follows DELETEDBL(INFO, FORW, BACK, START, AVAIL,LOC) 1. [Delete Node] Set FORW [ BACK [LOC]]:= FORW[LOC]& BACK [FORW[
Post-order Traversal This can be done both iteratively and recursively. The iterative solution would need a change of the in-order traversal algorithm.
Determine about the unreachable code assertion An unreachable code assertion is an assertion that is placed at a point in a program that shouldn't be executed under any circum
for i=1 to n if a[i}>7 for j=2 to n a[j]=a{j}+j for n=2 to n a[k]=a[j]+i else if a[1]>4 && a[1] for 2 to a[1] a[j]= a{j]+5 else for 2to n a[j]=a[j]+i ..
Example: Assume the following of code: x = 4y + 3 z = z + 1 p = 1 As we have been seen, x, y, z and p are all scalar variables & the running time is constant irrespective
Q. Make a BST for the given sequence of numbers. 45,32,90,34,68,72,15,24,30,66,11,50,10 Traverse the BST formed in Pre- order, Inorder and Postorder.
A depth-first traversal of a tree visits a nodefirst and then recursively visits the subtrees of that node. Similarly, depth-first traversal of a graph visits a vertex and then rec
Ask question 1. Indicate whether each of the following properties is true for every Huffman code. a. The codewords of the two least frequent symbols have the same length. b. The
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