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Step-1: For the current node, verify whether it contain a left child. If it has, then go to step-2 or else go to step-3
Step-2: Repeat step-1 for left child
Step-3: Visit (that means printing the node in our case) the current node
Step-4: For the current node verify whether it contain a right child. If it contain, then go to step-5
Step-5: Repeat step-1 for right child
Figure: A binary tree
The preoreder & postorder traversals are similar to that of a general binary tree. The general thing we have seen in all of these tree traversals is that the traversal mechanism is recursive inherently in nature.
Best Case: If the list is sorted already then A[i] T (n) = c1n + c2 (n -1) + c3(n -1) + c4 (n -1) = O (n), which indicates that the time complexity is linear. Worst Case:
algorithm to search a node in linked list
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12345 SOLVE BY USING FOLDING METHOD
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