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1/p+1/q+1/x=1/p+q+x find x
I dont understand why the least common denominator to the problem (3/2x) minus (1/2(x+10)) equals 1 is 2x(x+10)
the sum of three consecutive odd integers is -195. find the three integers.
x2 -x = 7 -3 -5 1 5 -3
6[5b+9]=2b+9.
a^4b+a^2b^3
x + y =2 , 2x- y =0
How do you do out a substitution problem and then graph it?
x 8/9 + = 6
|60-10*5|-11|2-16|
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