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If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2 from the problem(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n) then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2a^n(a-b)=b^n(a-b)then (a/b)^n=1=(a/b)^0from this equate the powersthen n=0
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Find the common difference of an AP whose first term is 100 and sum of whose first 6 terms is 5 times the sum of next 6 terms. Ans: a = 100 APQ a 1 + a 2 + ....... a 6
Find the Determinant and Inverse Matrix (a) Find the determinant for A by calculating the elementary products. (b) Find the determinant for A by reducing the matrix to u
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4x-5y+16=0
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