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If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2 from the problem(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n) then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2a^n(a-b)=b^n(a-b)then (a/b)^n=1=(a/b)^0from this equate the powersthen n=0
3v2
tan9x = (tan7x + tan2x)/(1 - tan7x*tan2x) here its given 1 - tan2x*tan7x= 0 implies tan9x = infinity since tan9x = (3tan3x - tan^3(3x))/(1 - 3tan^2 (3x)) = infinity implies
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There is a number. If the sum of digits is 14, and if 29 is subtracted from the number, the digits become equal. Find the number.
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Provide me some Examples of solve quadratic equations by Factorization
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