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If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2 from the problem(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n) then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2a^n(a-b)=b^n(a-b)then (a/b)^n=1=(a/b)^0from this equate the powersthen n=0
find the value of 0 that makes cos 21 degrees = sin 0 statement true.
need help with future value project
Find the sum of first 40 positive integers divisible by 6 also find the sum of first 20 positive integers divisible by 5 or 6. Ans: No's which are divisible by 6 are
Mike sells on the average 15 newspapers per week (Monday – Friday). Find the probability that 2.1 In a given week he will sell all the newspapers
sin 30
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Let D = 1 denotes the event that an adult male has a particular disease. In the population, it is known that the probability of having this disease is 20 percent, i.e., Pr (D = 1)
how do u do it
Solve the equation for x and check each solution. 2/(x+3) -3/(4-x) = 2x-2/(x 2 -x-12)
sin^2alpha *sec^2beta +tan^2 beta *cos^2alpha=sin^2alpha+tan^2 beta
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