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If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2 from the problem(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n) then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2a^n(a-b)=b^n(a-b)then (a/b)^n=1=(a/b)^0from this equate the powersthen n=0
What is Permutations explain with examples? Each arrangement of a set of elements is called a permutation. In other words, every possible way (order) of writing a group of lett
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20+20
x=±4, if -2 = y =0 x=±2, if -2 = y = 0
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On your geometry test you have two triangles: ?ABC and ?MNO. You are told that ?A ? ? M and that ?B ? ? N. Which statement is also true?
I need help with one logarithm problem
Inverse Cosine : Now see at inverse cosine. Following is the definition for the inverse cosine. y = cos -1 x ⇔ cos y = x for
how much is this
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