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If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2 from the problem(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n) then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2a^n(a-b)=b^n(a-b)then (a/b)^n=1=(a/b)^0from this equate the powersthen n=0
Consider the wave equation utt - uxx = 0 with u(x, 0) = f(x) = 1 if-1 ut(x, 0) = ?(x) =1 if-1 Sketch snapshots of the solution u(x, t) at t = 0, 1, 2 with justification (Hint: Sket
I need to follow the pattern .125,.25,.375,.5, ?
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Lines EF and GH are graphed on this coordinate plane. Which point is the intersection of lines EF and GH?
Combined Mean And Standard Deviation Occasionally we may need to combine 2 or more samples say A and B. Therefore it is essential to identify the new mean and the new standard
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