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If a^n+1 + b^n+1/a^n + b^n is the arithmetic mean of a and b then find n.
Answer:Arithmatic mean of a,b is =(a+b)/2 from the problem(a+b)/2=(a^n+1 +b ^n+1)/(a^n+b^n) then (a+b)(a^n+b^n)=(a^n+1 +b ^n+1)*2a^n(a-b)=b^n(a-b)then (a/b)^n=1=(a/b)^0from this equate the powersthen n=0
Properties of Logarithms 1. log a xy = log a x + log a y 2. = log a x - log a y 3. log a x n = n log
-nCr
2/4t=1/2
a boy is six months old his sister was given birth to three month after him. if their cousin is 0.33years old, arrange their ages in ascending order
Calculate the value of the following limits. Solution To remind us what this function such as following the graph. hence, we can see that if we reside to the r
is 1 and 1/2+2 and 1/7 3 and 9/4
two circle of radius of 2cm &3cm &diameter of 8cm dram common tangent
solve by factorization method; 10x-6y-3z=100, -6x+10y-5z=100, -3x-5y+10z=100
what is rotation
LAST COST METHOD
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