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In this unit, the following four advanced data structures have been practically emphasized. These may be considered as alternative to a height balanced tree, i.e., AVL tree.
The key factors that have been discussed in this unit about the above mentioned data structures include complexity of code in terms of Big oh notation, cost involved in searching a node, the process of deletion of a node and the cost involved in inserting a node.
After going through this unit, you should be able to:
Example: (Double left rotation while a new node is added into the AVL tree (RL rotation)) Figure: Double left rotation when a new node is inserted into the AVL tree A
An unsorted array is searched through linear search that scans the array elements one by one until the wanted element is found. The cause for sorting an array is that we search
Question 1 Discuss the following theorems with respect to Splay Trees- Balance Theorem Dynamic Finger Theorem Question 2 Write a C program for implementation
7. String manipulation 7.a Write a C Program using following string manipulation functions a) strcpy b) strncpy c) strcmp d) strncmp e) strlen f) strcat
State in detail about the Integer Carrier set of the Integer ADT is the set {..., -2, -1, 0, 1, 2, ...}, and operations on these values are addition, multiplication, subtrac
5. Implement a stack (write pseudo-code for STACK-EMPTY, PUSH, and POP) using a singly linked list L. The operations PUSH and POP should still take O(1) time.
You have to sort a list L having of a sorted list followed by a few "random" elements. Which sorting methods would be especially suitable for this type of task? Insertion sort
There are ten stations on a railway line: Train travels in both directions (i.e. from 1 to 10 and then from 10 to 1). Fare between each station is $2. A passenger input
Q. What is the smallest value of n such that an algorithm whose running time is 100n2 runs faster than an algorithm whose running time is 2n on the same machine. A n
Ask question find frequency count of function- {for(i=1;i {for(j=1;j {for(k=1;k } } }
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