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The actual solution is the specific solution to a differential equation which not only satisfies the differential equation, although also satisfies the specified initial conditions.
Illustration: What is the actual solution to the subsequent IVP?
2ty' + 4y = 3; y(1) = -4
Solution: This is in fact easier to do than this might at first appear. From the earlier illustration we already identify that differential equations have all solutions are of the form:
y(t) = 3/4 + c/t2
All that we require to do is find out the value of c that will provide us the solution that we're after. To determine this all we require do is utilize our initial condition that are given as:
-4 = y(1) = 3/4 + c/12
c= -4 -3/4 = -19/4
Thus, the actual solution to the Initial Value Problem is:
y(t) = ¾ - 19/4t2
From this last illustration we can notice that once we have the general solution to a differential equation determining the actual solution is nothing more than applying the initial conditions and resolving for the constants which are in the general solution.
i need help in discrete mathematics on sets, relations, and functions.
ogive for greater than &less than curves
Given that f(x,y) = 3xy - x 2 y - xy 2 . Find all the points on the surface z = f(x, y)where local maxima, local minima, or saddles occur
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2/4t=1/2
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THE FIRST AND THIRD TERM OF A G.P ARE 8 AND 18 RESPECTIVELY AND THE COMMON RATIO IS POSITIVE.FIND THE COMMON RATIO
Multiply and divide by root2, then root2/root2(sinx+cosx) = root2(sinx/root2 + cosx/root2) = root2(sinx cos45+cosx sin45) = root2(sin(x+45))
how do I solve 14/27 - 23/27 =
Let R be the relation on S = {1, 2, 3, 4, 5} defined by R = {(1,3); (1, 1); (3, 1); (1, 2); (3, 3); (4, 4)}. (b) Write down the matrix of R. (c) Draw the digraph of R.
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