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Accessing the Operands:
-registers (32 int, 32 fp)
-memory (232locations)
-simple to specify
-shut to the processor (fast access)
-normally all arithmetic instructions only access registers
-just access memory with explicit and stores and loads.
Load-store architectures
It can do: add r1=r2+r3 and then load r3, M(address)
⇒forces serious dependence on registers, which is accurately what you desire in today's CPU can't do add r1 = r2 + M(address)
- Other more instructions
+ Fast implementation (for example: easy pipelining)
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Convert (177.25) 10 to octal Ans. 177.25) 10 = ( ) 8 Firstly we take integer part Hence (177) 10 = (261) 8 Now as 0.25 x 8 = 2.00 and 0.00 x 8 = 0 Therefor
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One Erlang is equal to (A) 3600 CCS (B) 36 CCS (C) 60 CCS (D) 24 CCS Ans: One Erlang is equivalent to 3600 CCS.
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