Ac motors, Electrical Engineering

Assignment Help:

  AC Motors

DC motors that have their magnetic fields produced by coils as described earlier can, in principle,  be powered from AC as well, since if the applied voltage reverses (as it does in ac), then the current  in both the rotor and stator coils will reverse together, leading to no change in the direction of the torque produced. This is not the case if the magnetic fields   are produced   by permanent magnets instead of coils. In practice, energising a motor designed for DC with AC may not be very efficient because the manufacturer may not have made the motor from materials that reduce eddy current losses, expecting this not to be important (which it isn't for DC).

 

The main distinction between a motor and a generator is that, in a motor the rotr back emf is less than the applied voltage by an amount  equal to  the voltage drop across the armature (and field coil if series connected) resistance whilst in a generator the back emf is larger than the supplied voltage for the same reason. If the stator windings of the AC alternator described above were energised by ac, then

 

the   machine   would   work   as   a   motor instead, provided the rotor was turning at exactly the right speed so that each time a rotor pole approached a stator winding, the field  direction  in  that  winding  was  such that a torque was produced in the direction of motion. For this to occur, the rotor must turn  at  the  same  speed  that  would  be needed to create the frequency of voltage being applied to the stator. For this reason, such a machine is called a 'synchronous motor'.

 

A brushless version is often preferred  in which the rotor field is produced by permanent magnets rather than a coil. The power   available   from   such   motors   is limited to <50kW.The main problem with this type of motor is running it up to the synchronous speed in the first place. If it is not very close to the synchronous speed, it will not turn at all. An auxiliary motor is required to achieve the synchronous speed, after which the main motor can take over. Because of these starting problems, it has limited use, mainly applications that do not require the motor to start and stop very often. More recently, this problem can be overcome by using modern power electronic drives that start the motor with very low frequency ac and gradually increase the frequency of the supply as the rotor speeds up, keeping the rotor close to synchronism. The motor is usually fitted with a rotor position sensing device  so  that  the  electronics  can  check that  the rotor is indeed  staying synchronous with the  applied  stator frequency.

 

To  avoid  such  problems,  a  very  widely used alternative form of synchronous motor is the 'induction motor'

 

 


Related Discussions:- Ac motors

Ac motors, If the stator windings of an alternator were to be supplied ...

If the stator windings of an alternator were to be supplied by an AC of frequency f (as opposed to drawing an AC current from them as would be the case for an alternator) then

Direct addressing , Direct Addressing In this  addressing  mode one  o...

Direct Addressing In this  addressing  mode one  of the  operands is the  data stored  in the memory. The memory  address of the  operand is directly  given in the instruction

Two-winding distribution transformer, Q. A single-phase, 10-kVA, 2300:230-V...

Q. A single-phase, 10-kVA, 2300:230-V, 60-Hz, two-winding distribution transformer is connected as an auto transformer to step up the voltage from 2300 V to 2530 V. (a) Draw a s

Stack pointer, stack Pointer (SP) It is also a 16 bit  register and a  ...

stack Pointer (SP) It is also a 16 bit  register and a  memory  pointer similar to  program counter. It holds  the memory  address of the  top of the stack. Stack is a  part of

Design a circuit using real components, The circuit shown below is a protot...

The circuit shown below is a prototype 4 th - order low-pass filter which is required to meet the specification given. However the specification is not met due to inadequate atten

Determine voltage in given figure, Q. An n-channel JFET having V P = 3.5 V...

Q. An n-channel JFET having V P = 3.5 V and I DSS = 5 mA is biased by the circuit of Figure with V DD = 28 V, RS = 3000 , and R 2 = 100 k. If the operating point is given by

Determine the form factor and peak factor, Determine the form factor and pe...

Determine the form factor and peak factor: Determine the form factor and peak factor for the above half rectified wave. Solution From the above example, I rms   =

Give a brief description of integrating circuits, Q. Give a brief descripti...

Q. Give a brief description of integrating circuits ? Integration is a summation of area. An integrating circuit produces an output voltage which is proportional to the area en

Pdc, disadvantages of shunt&series clippers

disadvantages of shunt&series clippers

Microcontroller, Project Garage door opener with password. Wrong password ...

Project Garage door opener with password. Wrong password "door close" on lcd screen, correct password "door open" on lcd Screen no need the motor. Material used - Microcontroller

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd