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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
f(x)=x^2+6x+5 given f(2)
Solve following. |2x - 5 |= 9 Solution Now, recall that absolute value does not just make all minus signs in plus signs. In order to sol
p(x)=x-a
-56
a 9f2 square painting is mounted with border on a square frame. if the total area of the border is 3.25 ft2, what is the length of a side of the frame?
A police academy is training 14 new recruits. Some are working dogs and others are police officers. There are 38 legs in all. How many of each type of recruits are there?
-16 = n + 1
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Given f ( x ) = 3x - 2 find f -1 ( x ). Solution Now, already we know what the inverse to this function is as already we've done some work with it. Though, it would be n
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