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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
Here are two one-to-one functions f (x ) and g ( x ) if (f o g )( x ) = x AND ( g o f ) ( x ) = x then we say that f ( x )& g ( x ) are
y+11=(y+10)+(y-7)
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??2+??2+16??-18??+145=25 Standard form (x-h)^2 +(y-k)^2 k (x^2+16x+64)^2+(y^2-18y+81)^2=25 (x+8)^2+(y-9)^2=120 (h,k)=(8,-9) R=5 Intercepts
x=y=3 , 2x-y=5
a+1/2=1
I have a homework question to use the factor theorem that I need to use Synthetic Substitution with. I did all the work and the divisor is a factor but the equation I have to use t
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R1 U R2
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