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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
what is 6(5*-6)
the problem is 6x+3y=-24. is tells me to graph using y=mx+b format but i don''t know how to get to that point.
Simplify 3(x-2)to the second -2(x+1)
solve log(5*8)
What we desire to do in this section is to begin with rational expressions & ask what simpler rational expressions did we add and/or subtract to obtain the original expression. The
f(x)-4x+4 find f(x+h)-f(x)/h
Show that x+3 is a factor of f(x)=3x4 - 3x3 - 36x2. Then factor f(x) completely.
32+3e=
Interval notation The next topic that we have to discuss is the idea of interval notation. Interval notation is some very pleasant shorthand for inequalities & will be utilize
3x-y+2z=14 x+y-z=0 2x-y+3z=18
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