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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
4x^2+8x-16=0
We can also indicate a strict mathematical/formula definition for absolute value. It is, It tells us to look at the sign of p & if it's positive we just drop the absolute
x+y=6 -x+y=-6 how do I write that in order to graph it?
Sketch the graph parabolas. f (x ) = 2 ( x + 3) 2 - 8 Solution In all of these we will just go through the procedure given above to determine the required points and t
Now, let's solve out some double inequalities. The procedure here is alike in some ways to solving single inequalities and still very different in other ways. As there are two ineq
find the domain and range of f(X)=2*3^x+5
-56
y+5=(4x+1)
Example Evaluate log 5 7 . Solution At first, notice that we can't employ the similar method to do this evaluation which we did in the first set of instance. It would n
Graph each equation, and determine the domain and range. determine whether the equation is a function.
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