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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
Let's begin with x 2 + bx and notice that the x 2 hold a coefficient of one. That is needed in order to do this. Now,
solve 3 different ways (3/x to the 2 power) to the -3power
Sketch the graph through the process of finding the zeroes Example Sketch the graph of P ( x ) = x 4 - x 3 - 6x 2 . Solution
6-5+3h*5h
-16 = n + 1
Example Sketch the graph of the common logarithm & the natural logarithm on the similar axis system. Solution This instance has two points. Firstly, it will familiarize u
I need help with complex fractions
a+1/2=1
i need help with linear functions in pre algebra i have a test tomorrow and i need help with the concept and ways to remeber it thank you! mackenzie
how to solve simplex method
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