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In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to examine two separate cases.
Inequalities Involving < and ≤
As we did with equations let's begin by looking at a fairly simple case.
p ≤ 4
This says that no matter what p is it ought to have a distance of no more than 4 from the origin. It means that p have to be somewhere in the range,
-4 ≤ p ≤ 4
We could have alike inequality with the < and obtain a similar result.
Generally we have the following formulas to use here,
If |p| ≤ b, b = 0 then - b ≤ p ≤ b
If |p| < b, b =0 then - b < p < b
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Solve following. 2 x - 4 = 10 Solution There actually isn't much to do other than plug into the formula. As with equations p merely represents whatever is within the a
Here are two one-to-one functions f (x ) and g ( x ) if (f o g )( x ) = x AND ( g o f ) ( x ) = x then we say that f ( x )& g ( x ) are
factor out the greatest common fctor
Solve following. 2x - 3 = 7 Solution Again, p represents the quantity within the absolute value bars thus all we have to do here is plug into the formula & then solve th
I don''t understand it
I need examples for a tutorial I have do in my AVID class.
(2a 3b 0 ) – 3 C 2
5+5
y=mx+b for x
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