Aad-arithmetic instruction-microprocessor, Assembly Language

Assignment Help:

AAD: ASCII Adjust for Division though the names of these 2 instructions (AAM and AAD) seem to be same, there is many difference between their functions. The AAD instruction converts 2 unpacked BCD digits in AL and AH to the corresponding binary number in AL. This adjustment might be made before dividing the 2 unpacked BCD digits in the AX by an unpacked BCD byte. SF, PF, ZF are modified whereas CF, AF, OF are not defined, after the execution of the instruction AAD. The instance describes the execution of the instruction. This instruction seems before DIV instruction unlike the AAM seems after MUL in the instruction sequence. Assume AX has 0508 unpacked BCD for 58 decimal, and DH consist 02H.

Example :

1629_AAD.jpg

The conclusion of the AAD execution will give the hexadecimal number 3A in the AL and 00 in the AH. Notice that 3A is the hexadecimal correspondent of 58 (decimal). Now, the instruction DIV DH can be executed. So rather than ASCII adjust for division, it is ASCII adjust before division operation.  All the ASCII adjust instructions are also known as unpacked BCD arithmetic instructions.  Now, we will consider the two instructions related to the packed BCD arithmetic.

 


Related Discussions:- Aad-arithmetic instruction-microprocessor

Interrupt priority management-microprocessor, Interrupt Priority Management...

Interrupt Priority Management The interrupt priority management logic indicated in given figure can be implemented in several ways. It does not required to be present in system

Flowchart for the sequence of 8251-microprocessor, Flowchart for the sequen...

Flowchart for the sequence of 8251 Whether the control, mode or sync character register is selected depends on the accessing sequence.  A flowchart of the sequencing is given i

Segment registers-microprocessor, Segment Registers The 8086 addresses ...

Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea

8086, Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to inv...

Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to invert bits D7D6 of ax register

Assembly language, Assembly Language: Inside the 8085, instructions ar...

Assembly Language: Inside the 8085, instructions are really stored like binary numbers, not a very good manner to look at them and very difficult to decipher. An assembler is

Implement an assembly language program, A good starting point for your prog...

A good starting point for your program is the toupper.asm program shown in class. It already queries the user for input and sets up a loop that looks at each character of the input

Convert into hex pairs, Convert 751 to hex and show what it would look like...

Convert 751 to hex and show what it would look like stored at TheNumber WORD ? (hint: answer in hex pairs)

Program to average ten 16-bit values, Write a MC68HC12 assembly language pr...

Write a MC68HC12 assembly language program to average ten 16-bit values that are stored starting at address $1100. Place the two-byte result at $1110. Use indexed addressing. Us

Ret-unconditional branch instruction-microprocessor, RET : Return from the...

RET : Return from the Procedure:- At each CALL instruction, the register IP and register CS of the next instruction is pushed to stack, before the control is transferred to the

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd