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AAD: ASCII Adjust for Division though the names of these 2 instructions (AAM and AAD) seem to be same, there is many difference between their functions. The AAD instruction converts 2 unpacked BCD digits in AL and AH to the corresponding binary number in AL. This adjustment might be made before dividing the 2 unpacked BCD digits in the AX by an unpacked BCD byte. SF, PF, ZF are modified whereas CF, AF, OF are not defined, after the execution of the instruction AAD. The instance describes the execution of the instruction. This instruction seems before DIV instruction unlike the AAM seems after MUL in the instruction sequence. Assume AX has 0508 unpacked BCD for 58 decimal, and DH consist 02H.Example :
The conclusion of the AAD execution will give the hexadecimal number 3A in the AL and 00 in the AH. Notice that 3A is the hexadecimal correspondent of 58 (decimal). Now, the instruction DIV DH can be executed. So rather than ASCII adjust for division, it is ASCII adjust before division operation. All the ASCII adjust instructions are also known as unpacked BCD arithmetic instructions. Now, we will consider the two instructions related to the packed BCD arithmetic.
LENGTH : Byte Length of a Label: This directive is not available in MASM. This is used to mention to the length of a data array or a string. MOV CX. LENGTH ARRAY This sta
AAM: ASCII Adjust for Multiplication after execution. This instruction converts the product available in the AL into unpacked BCD format. This follows a multiplication instruct
Assembling a program Microsoft Assembler MASM is one of the simple to use and famous assemblers. All the references and discussions in this section are belonging to the MASM.
errorlevel -302 ;prevents error code for this chipset __config 0x373A ;chip config PIC spec page 146 processor 16F877A ;chipset reset code
Pointer and Index Registers The pointers contain offset within the specific segments. The pointers BP, IP and SP generally containoffsets within thedata, code and stack segment
I want to do a program as a game by using the Microcontroller 8051 with the assembly language, by using 4*4 keypad and its matrix display. I have to use the keypad for playing the
Open notepad and enter the code for a program that calculates the following arithmetic expression: x = a + b + c - d - e + f The operands a, b, c, d, e, f, and x should be declared
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
) What is the difference between re-locatable program and re-locatable data?
to separate positive and negative numbers
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