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A parallel plate capacitor, each with plate area A and separation d, is charged to a potential dissimilarity V. The battery used to charge it is then disconnected. A dielectric slab of thickness d and dielectric constant K is now placed among the plates. What change, if any, will take place in
1. Charge on the plates
2. Electric field intensity among the plates
3. Capacitance of the capacitor.
Justify your answer in each case.
It is the ratio of the internal electric field induced by the charges on the surface on the dielectric when an external field applied to the polarization of the dielectric.
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