A composable-reset DFA (CR-DFA) is a five-tuple, Theory of Computation

Assignment Help:

Question 2 (10 pt): In this question we look at an extension to DFAs. A composable-reset DFA (CR-DFA) is a five-tuple, (Q,S,d,q0,F) where:
– Q is the set of states,
– S is the alphabet,
– d:Q×(S?{?})?Qisthetransitionfunction, – q0 ? Q is the start state, and
– F ? Q is the set of accept states.
Every CR-DFA must satisfy one additional property:
When running a CR-DFA one can take a ?-transition if and only if the input has already been exhausted, and d cannot have any cycles that have a ?-transition.
A CR-DFA differs from a DFA by the addition of a new symbol denoted ? which can only be used by the transition function. This symbol is not part of the alphabet of the DFA.
The run function for a CR-DFA is defined as follows:
dˆ 0 : Q × S * × S * ? Q dˆ0(q,e,w1) = q
if d(q, ?) is undefined. dˆ0(q, e, w1) = dˆ0(q', w1, w1)
if d(q, ?) = q'
dˆ0(q, aw, w1) = dˆ0(q', w, w1)
if d(q, a) = q' dˆ : Q × S * ? Q
dˆ ( q , w ) = dˆ ( q , w , w ) 0
1
We can see that the run function, dˆ, is defined interms of an auxiliary function called dˆ0. The latter takes three arguments: i. the current state, the input word, and a second input word called w1. The second input word is called an accumulator, and it will be used to remember the original input to the run function, but when defining the auxiliary run function we leave this arbitrary.
The definition of the auxiliary run function follows the definition of the run function for DFAs, but in the case where the input word has been exhausted we check to see if the transition function allows the input to be reset to w1, and if it does, then we call dˆ0 on the next state given by d, and the input word is reset to w1. If when the input is exhausted and the transition function does not allow a ?-transition, then we proceed as usual.
Note that the definition of acceptance for a CR-DFA is the same as for DFAs.
We now define an interesting language. Suppose S = {a, b, c, d, ?, ?} is an alphabet. The symbol ? represents a binary operation, and the symbols a, b, c, d, and ? represent inputs to the binary operation ?. The language L is defined by the following:
i. a,b,c,d,? ? L
ii. Foranyei ?S,thewordw=e1?e2?e3?···?en ?L
iii. For any w ? L, any well-balanced parenthesization of w is a member of L
iv. There are no other words in L.
The following are some example words in L:
a
b
c
d
?
(a?b) (a?(b?c)) (a?(b?(c?d))) a?b?c (a?b)?c
So the words of L are all the possible associations of applications of the binary operation ?. Define a CR-DFA in the diagrammatic from used with DFAs that recognizes the language L as defined above. In addition, describe why CR-DFAs are bad in practice.

Related Discussions:- A composable-reset DFA (CR-DFA) is a five-tuple

Transition graphs, We represented SLk automata as Myhill graphs, directed g...

We represented SLk automata as Myhill graphs, directed graphs in which the nodes were labeled with (k-1)-factors of alphabet symbols (along with a node labeled ‘?' and one labeled

Possibility of recognizing the palindrome language, Computer has a single F...

Computer has a single FIFO queue of ?xed precision unsigned integers with the length of the queue unbounded. You can use access methods similar to those in the third model. In this

Applying the pumping lemma, Applying the pumping lemma is not fundamentally...

Applying the pumping lemma is not fundamentally di?erent than applying (general) su?x substitution closure or the non-counting property. The pumping lemma is a little more complica

Class of recognizable languages, Proof (sketch): Suppose L 1 and L 2 are ...

Proof (sketch): Suppose L 1 and L 2 are recognizable. Then there are DFAs A 1 = (Q,Σ, T 1 , q 0 , F 1 ) and A 2 = (P,Σ, T 2 , p 0 , F 2 ) such that L 1 = L(A 1 ) and L 2 = L(

Java programming, 1. An integer is said to be a “continuous factored” if it...

1. An integer is said to be a “continuous factored” if it can be expresses as a product of two or more continuous integers greater than 1. Example of continuous factored integers

Notes, write short notes on decidable and solvable problem

write short notes on decidable and solvable problem

Merging nodes, Another striking aspect of LTk transition graphs is that the...

Another striking aspect of LTk transition graphs is that they are generally extremely ine?cient. All we really care about is whether a path through the graph leads to an accepting

Equivalence problem, The Equivalence Problem is the question of whether two...

The Equivalence Problem is the question of whether two languages are equal (in the sense of being the same set of strings). An instance is a pair of ?nite speci?cations of regular

Prepare the consolidated financial statements, Prepare the consolidated fin...

Prepare the consolidated financial statements for the year ended 30 June 2011. On 1 July 2006, Mark Ltd acquired all the share capitall of john Ltd for $700,000. At the date , J

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd