8088 timing system diagram-Microprocessor, Assembly Language

Assignment Help:

8088  Timing System Diagram

The 8088 address/data  bus is divided  in 3 parts (a) the lower 8 address/data  bits, (b) the middle 8 address bits, and (c) the upper 4 status/address bits. The lower 8 lines are time multiplexed for data bus and address bus. The upper 4 lines are time multiplexed for address bus and status bus. Each of the bus cycles has T1, T2, T3, T4 and Tw states. The ALE signal goes high for one clock cycle in T1. The trailing edge of ALE is used to latch the valid addresses available on the multiplexed lines. They remain valid above the bus for the next cycle (T2). The middle 8 address bits are always present on the bus throughout the bus cycle. The lower order address bus is tristated after T2 to change its direction for read data operation. The real data transfer takes place during T4 and T3. Hence the data lines are valid in T3 / T4. The multiplexed bus is tristated again to be ready for the next bus cycle. The status lines are valid for the multiplexed address/status bus for T2, T3 and T4 clock cycles.

In case of write cycle, the timing diagram is similar to the read cycle except for the validity of data. The data bits are available in the write cycle on the bus for T2, T3, T4, and Tw. At the end of 14, the bus is tristated. The other signals WR, RD, INTA, DT/R, READY and DEN are similar to the 8086 timing diagram. Figure shows the details of read and writes bus cycles of 8088.

2332_8088 timing system.jpg

With an 8-bit external data bus, the 8088 has been designed for internal  16-bit  processing  capability. Closely all the internal functions of 8088 are equal to 8086. The 8088 utilized the external bus in the similar way as 8086, but only 8 bits of external data are accessed at a time. While writing or fetching the 16-bit data, the job is performed in 2 consecutive bus cycles. As the software is concerned, the chips are equal except in case of timings. The 8088, thus might take more time for execution of a particular task as compared to 8086.

 


Related Discussions:- 8088 timing system diagram-Microprocessor

Write policy-microprocessor, Write Policy A write policy determines how...

Write Policy A write policy determines how the cache deals with a write cycle. The 2 common write policies areWrite-Throughand Write-Back. In Write-Back policy, the cache behav

Aaa-arithmetic instruction-microprocessor, AAA: ASCII Adjust after Additio...

AAA: ASCII Adjust after Addition operation the AAA instruction is executed after an ADD instruction that adds 2 ASCII coded operands to give a byte of outcome in the AL. The AAA i

Synchronous and asynchronous transmissions of 8251, Typical link to modems ...

Typical link to modems for synchronous and asynchronous transmissions are shown in Figure. With regard to the synchronous connections it is consider that the timing is controlled

Program, wap proram for bthe addition of two 3*3 matrix

wap proram for bthe addition of two 3*3 matrix

#procedure, #Write a function to calculate the following arithmetic operati...

#Write a function to calculate the following arithmetic operation and return the result. A = 2 + (3x)3 + y/2n (x, y and n are arguments of the function where x is an integer in the

Assembler directives and operators-microprocessor, Assembler Directives and...

Assembler Directives and Operators The major advantage of machine language programming is directly that the memory control is in the hands of the programmer, so that, he can be

Physical memory mapped and port input output-microprocessor, Physical Memor...

Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention

Cache components-microprocessor, Cache components The cache sub-system ...

Cache components The cache sub-system may be divided into 3 functional blocks: Tag RAM, SRAM and theCache Controller. In real designs, these blocks can be implemented  by multi

Program to perform a conversion on characters in a text file, Write an asse...

Write an assembly language program to perform a rot13 1 conversion on characters in a text file.  The program should read charatcers from the input file, perform the rot13 convers

Assembly language assignment, The main objective of the assignment is to ex...

The main objective of the assignment is to explore the knowledge regarding parallel ports of a computer system. You can read and write datato/from the parallel port using IN and OU

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd