8088 timing system diagram-Microprocessor, Assembly Language

Assignment Help:

8088  Timing System Diagram

The 8088 address/data  bus is divided  in 3 parts (a) the lower 8 address/data  bits, (b) the middle 8 address bits, and (c) the upper 4 status/address bits. The lower 8 lines are time multiplexed for data bus and address bus. The upper 4 lines are time multiplexed for address bus and status bus. Each of the bus cycles has T1, T2, T3, T4 and Tw states. The ALE signal goes high for one clock cycle in T1. The trailing edge of ALE is used to latch the valid addresses available on the multiplexed lines. They remain valid above the bus for the next cycle (T2). The middle 8 address bits are always present on the bus throughout the bus cycle. The lower order address bus is tristated after T2 to change its direction for read data operation. The real data transfer takes place during T4 and T3. Hence the data lines are valid in T3 / T4. The multiplexed bus is tristated again to be ready for the next bus cycle. The status lines are valid for the multiplexed address/status bus for T2, T3 and T4 clock cycles.

In case of write cycle, the timing diagram is similar to the read cycle except for the validity of data. The data bits are available in the write cycle on the bus for T2, T3, T4, and Tw. At the end of 14, the bus is tristated. The other signals WR, RD, INTA, DT/R, READY and DEN are similar to the 8086 timing diagram. Figure shows the details of read and writes bus cycles of 8088.

2332_8088 timing system.jpg

With an 8-bit external data bus, the 8088 has been designed for internal  16-bit  processing  capability. Closely all the internal functions of 8088 are equal to 8086. The 8088 utilized the external bus in the similar way as 8086, but only 8 bits of external data are accessed at a time. While writing or fetching the 16-bit data, the job is performed in 2 consecutive bus cycles. As the software is concerned, the chips are equal except in case of timings. The 8088, thus might take more time for execution of a particular task as compared to 8086.

 


Related Discussions:- 8088 timing system diagram-Microprocessor

Project 1: Text Conversion, I need a text conversion program written in ass...

I need a text conversion program written in assembly language

Code using hla language, You have been hired by the Elbonian government to ...

You have been hired by the Elbonian government to write an Assembly program to help its workforce determine how much their tax will be. The tax laws in Elbonian are very simple. Th

8086 minimum mode system and timing-microprocessor, 8086 Minimum mode Syst...

8086 Minimum mode System and Timing In a minimum mode 8086 system, the microprocessor 8086 is operated in minimum mode by strapping its MN/MX pin to logic 1.All the control si

Comparison between 8086 and 8088, Comparison between 8086 and 8088 All ...

Comparison between 8086 and 8088 All the changes in 8088 above 8086 are indirectly or directly related to the 8-bit, 8085 compatible data and control bus interface. 1) The p

Assembly Language Programming, Write a program that defines symbolic consta...

Write a program that defines symbolic constants for all of the days of the week

Addressing mode of 8086-microprocessor, Addressing mode of 8086 : Addre...

Addressing mode of 8086 : Addressing mode specify a way of locating operands or data. Depending on the data types used the memory  addressing  modes and in the instruction  ,

Dma hardware (8237 dmac)-microprocessor, DMA Hardware (8237 DMAC) : ...

DMA Hardware (8237 DMAC) :   1)Processor contain HOLD/HOLD Acknowledge lines to interact with 8237 o   DMAC can achieve control of ISA bus by asserting HOLD o   P

ADDITION-SUBTRACTION, HELLO I AM TRYING TO ADD AND SUBTRACT BUT I SEEM CAN'...

HELLO I AM TRYING TO ADD AND SUBTRACT BUT I SEEM CAN''T FIND THE CORRECT REGISTER TO PUT IN

Intel''s 8237 dma controller-microprocessor, Intel's 8237 DMA controller : ...

Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)

Selecting array elements, implement the following c++ code in assembly lang...

implement the following c++ code in assembly language using the block-structured .IF and .while directives

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd