8088 associated with 8259 a-microprocessor, Assembly Language

Assignment Help:

For an 8088 the 2 addresses linked with an 8259A are normally consecutive, and the AO line is associated to the AO pin, but because there are just 8 data pins on the 8259A and the 8086 always inputs the interrupt pointer from the lower 8 bits of its 16-bit data bus, all data transfers to and from the 8259A might be made over the lower byte of the bus. The simplest way to guarantee that all transfers will utilize the lower half of the bus is to attach the Al line to AO and utilize two consecutive even addresses, with the first being divisible by four. However, to simplify the discussion, the second address will be referred to as the odd address for both cases.

The control portion of the 8259A contains several programmable bits that can be viewed as being contained in seven 8-bit registers. These group  containing  the  operation  command  words (OCWs). The starting command words are usually set by an beginner routine when the computer system  is  first  brought  up  and  remain constant  throughout its whole operation.   Contrastively, the operation command words are utilized to dynamically control the processing of interrupts.

The IRR (and its linked masking logic), and priority resolver, are for controlling and receiving the interrupts that arrive at the pins IR7-IRO. The IRR latches the incoming requests and, in conjunction having the priority resolver, let unmasked requests with enough priority to put a one on the INT pin. The priority resolver logic determines the priorities of the requests in the IRR and the ISR is used for holding the requests currently being processed.

After a bit in the IRR is set to one it is compared with the equivalent mask bit in the IMR. If the mask bit value is set zero the request is passed on to the priority resolver, but if the value is 1, the request is blocked. When an interrupt request is input to the priority resolver its priority is checked and, if according to the current state of the priority resolver the interrupt is to be sent to the CPU and the INT line is activated.

Supposing  that the IF flag in the CPU is 1, the CPU will go to its interrupt sequence at the completion of the current instruction and return 2 negative pulses on the INTA line. On the arrival of the first pulse, the IRR latches are disabled so that the IRR will avoid further signals on the IR7-IRO lines. This state is maintained till the end of the second INTA pulse.  The first INTA pulse will also cause the suitable ISR bit to be set and the corresponding IRR bit to be cleared. The 2nd INTA pulse make the current contents of ICW2 to be placed on the D7-DO, and the CPU utilize this byte as the interrupt type. If the automatic end of interrupt (AEOI) bit in ICW4  value is set one, at the end of the second INTA pulse the ISR bit that was set by the first INTA pulse is cleared; or else the ISR bit is not cleared till the accurate end of interrupt (EOI) command is sent to OCW2.

As show above, the initialization command words are usually filled by an initializing routine when the system is turned on and have the control bits that are held constant throughout the system's operation. The  8259A  has  an  even  address  (AO  =  0)  and  an  odd  address  (AO  = 1)  linked  with  it  and  the initialization command words might be filled consecutively using the even address for ICWI and the odd address for the remaining ICWs.

 


Related Discussions:- 8088 associated with 8259 a-microprocessor

Compute the fibonacci sequence - assembly program, Compute the Fibonacci se...

Compute the Fibonacci sequence - assembly program: Problem: Fibonacci   In this problem you will write a program that will compute the first 20 numbers in the Fibonacci sequ

Efficient assembly language program, (1) Write a program that will: (a) dis...

(1) Write a program that will: (a) display "Enter Your Name:" (b) convert the entered name to Capital letters (if small), If any other character is entered, the program wil

Merge Sort, Write a program to merge two sorted arrays to create a third so...

Write a program to merge two sorted arrays to create a third sorted array containing all values from the two original arrays. Merge is a key component to the mergesort algorithm.

Execution unit and bus interface unit-microprocessor, Execution Unit (EU) a...

Execution Unit (EU) and Bus Interface Unit (BIU) : 8086 consist of two processors called EU and BIU. Two Processors can work parallel. This improves speed of execution. BIU fi

Cobol, #I submitted my assignment this morning and it is still processing. ...

#I submitted my assignment this morning and it is still processing. How long does it take?

Memory address decoding-microprocessor, Memory Address Decoding Binary ...

Memory Address Decoding Binary Decoders - Decoders have 2n-inputs and n outputs, each input combination results in a single output line contain a 1, and all other lines contain

Internal architecture of microprocessor, Internal Architecture of Microproc...

Internal Architecture of Microprocessor : The architecture of 8086 provides a number of improvements over 8085 architecture. It supports a, a set of 16-bit registers ,16-bit AL

Name-offset-assemblers directive-microprocessor, NAME : Logical Name of...

NAME : Logical Name of a Module: The NAME directive which is used to assign a name to an assembly language program module. The modulecan now be mention to by its declared name.

Org-proc-assemblers directive-microprocessor, ORG : Origin:- The ORG di...

ORG : Origin:- The ORG directive directs the assembler to begin the memory allotment for the specific segment, code or block from the declared  address in the ORG  statement. W

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd