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describes vertical and horizontal web services protocols. Next, identify the similarities and differences between vertical and horizontal web services protocols. Finally, explain w
to separate positive and negative numbers
Displacement addressing technique
Example : Add the contents of the 2000H: 0500H memory location to contents of 3000H: 0600H and store the result in 5000H: 0700H. Solution : Unlike the past example progra
using 8086 assembly language that interchange upper four bits to lower four bits. assume that data store in byte memory and it written back to same location. and assume the data as
AAS: ASCII Adjust AL After Subtraction AAS instruction correct the result in the AL register after subtracting operation of two unpacked ASCII operands. The result is in unpacked
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Memory Mapped I/O Memory I/O devices are mapped into the system memory map with ROM and RAM. To access a hardware device, simply write or read to those 'special' addresse
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