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CANI GET HELP WRITTING THIS CODE
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
SUB: Subtract :- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory locati
SEG : Segment of a Label:- The SEG operator is which is used to decide the segment address of the, variable, label or procedure and substitutes the segment base address in plac
Display control 8279 provides a 16 byte display memory and refresh logic. Every address in the display memory corresponds to a display unit with address zero represen
Explain the architecture of the file transfer protocol ftp in terms of clients, servers, sockets
Write an account of your findings and produce a report containing all aspects of the above. Include a step-by-step 'simple User Guide' so that your program can be operated as inten
a- Trace the following program fragment and find out the content of ax after the the execution of the program. X db 5,7 -3,-9,4,-7,9 Mov
64-bit integer calculator, which processes using 16-bits at a time (reg/mem16 operands)
OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar
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