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what is the value of integration limit n-> infinity [n!/n to the power n]to the power 1/n
Solution) limit n-->inf. [1 + (n!-n^n)/n^n]^1/n
= e^ limit n-->inf. {(n!-n^n)/n^n}.1/n
(applying formula lim x-->a [1 + f(x)]^g(x) = e ^ {lim x-->a f(x).g(x)} )
=e ^ lim n-->inf. (n-1)!/(n)^n-1 - 1/n
=e ^ lim n---> inf. (1-1/n)(1-2/n)(1-3/n)......1/n - 1/n
=e ^ (1-o)(1-0).....(1-0).0 - 0
=e ^ 0-0
=1
hence, integation 1= x + C
Apply depth-first-search to find out the spanning tree for the subsequent graph with vertex d as the starting vertex. Ans: Let us begin with node'd'. Mark d as vi
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-255=-14t-t
If we "break up" the root into the total of two pieces clearly we get different answers. Simplified radical form: We will simplify radicals shortly so we have to next
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one half y minus 14
How do you find the area of a circle given the diameter?
no the parallel lines do not meet at infinity because the parallel lines never intersect each other even at infinity.if the intersect then it is called perpendicuar lines
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