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A certain radioactive substance has a half-life of 40 minutes. How much of an original 100 grams substance will remain after 2 hours? solution) m= m0/2t/Tm=100 gms..t=2 hours=2*60=120 min..T=40 minm=100/2120/40m=100/23m=100/8m=12.5 gms.
A 3Kg bar of aluminum has to be heated from 25 degrees Celsius to 75 degrees Celsius. how many calories are needed to achieve this temperature increase?
A monochromatic light of wavelength 6000Å is incident on a plane diffraction grating with grating element 6 X 10 -5 cm. Evaluate the maximum order of spectrum that will be observe
Construction of UJT The fundamental structure of a UJT is illustrated in fig. (a). It comprises an n-type silicon bar that is lightly doped. Two end connections are taken fr
A charge is said to be in equilibrium, if total force performing on it is zero. A operation of charges is said to be in equilibrium if every charge is independently is equilibrium.
Ferromagnetic Substance: A substance which behaves as a magnet in presence of a strong magnetic field is known as ferromagnetic substance. E.g. Iron, Nickel
#questionMnS is a paramagnetic solid. At 300°K, there are 4 × 1022 molecules of MnS per cm3. If the cationic magnetic moment of MnS is 5 MB, use the Curie law in 8-b to compute the
#question 1:successive disintegration in nucluer physics
Characteristics of Resistance in parallel: Different amount of current passing by each resistance. i.e. I = I1 + I2 + I3 + I4 ........ The potential difference across every
if a 5-kg object experience a 10-n force for a 0.10-second, then what is momentum change of the object
EXAMPLES OF IT
half life = 40minutes =2/3 hourst(1/2)=(ln2 /k)then k=(ln2/t(1/2)) = ln2/(2/3) = 3/2*(ln2)origianl substance y0= 1000 gramsy=y0e-kty= 1000*(e-(3/2(ln2))*2 ) = 1000/8 = 125 grams
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