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A certain radioactive substance has a half-life of 40 minutes. How much of an original 100 grams substance will remain after 2 hours? solution) m= m0/2t/Tm=100 gms..t=2 hours=2*60=120 min..T=40 minm=100/2120/40m=100/23m=100/8m=12.5 gms.
Cross Product The direction of the cross product of 2 vectors is elaborates. The magnitude shown is correct but not discussed.
Copper losses: These losses occur because of ohmic resistance of the transformer windings. If I1 and I2 are primary and secondary currents correspondingly and R1and R2 are the res
Oxygen effect: The oxygen effect may play a role in the recurrence of cancer .The cell near the center of a large tumor have a poor blood supply and thus a poor oxygen supply
dynamic resistance
Write the mathematical relation for the resistivity of a material in terms of relaxation time, number density and mass and charge of charge carriers in it. Describe, using this rel
Explain the terms (i) magnetic declination and (ii) angle of dip at a given place.
A rectangular rosette is mounted on a test structure as shown, loads are applied, and the following strains are measured by strain gage elements 1, 2, and 3: ε 1 = 1500 μm/ m ε
Cathode rays, discovered by Sir Willium Crooke are the stream of electrons. They may be given by using a discharge tube containing gas at a low pressure of the order of 10-2 mm of
#question.introduction .
In a pure semiconductor, concentration of electrons in conduction band is equal to the concentration of holes in valence band. In the process of conduction when an electric field i
half life = 40minutes =2/3 hourst(1/2)=(ln2 /k)then k=(ln2/t(1/2)) = ln2/(2/3) = 3/2*(ln2)origianl substance y0= 1000 gramsy=y0e-kty= 1000*(e-(3/2(ln2))*2 ) = 1000/8 = 125 grams
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