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A certain radioactive substance has a half-life of 40 minutes. How much of an original 100 grams substance will remain after 2 hours? solution) m= m0/2t/Tm=100 gms..t=2 hours=2*60=120 min..T=40 minm=100/2120/40m=100/23m=100/8m=12.5 gms.
Hf = mLf m - (g/lbs) *1lb = 454g Lf - latent heat of fusion - 80 kcal/kg fr water Hope
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Ehrenfest paradox (Ehernfest, 1909) The special relativistic "paradox" including a quickly rotating disc. As any radial segment of the disc is perpendicular to the direction o
What is the principle and ray diagram of a compound microscope
The temp gradient is similar to finding the slope of a line (when in two dimensions) Temp. Gradient= Change in Temp. value/Distance. dT/dx = (T2 - T1)/(X2 - X1)
There are two major differences between "center of gravity" and "center of mass": 1) The term "center of gravity" aplies to the bodies with mass and weight, while the term "cent
a) Amplitude : It is the main value of distance of the particle from its equilibrium position. b) Time period (T): Smallest time interval after which the oscillatory motion
newton''s law
The integral in Ampere's Law is an integral. Answer: The integral is an integral along (over) a closed path (curve).
On transitory from a medium with one index of refraction to a medium with a different index of refraction light is typically both reflected and refracted. Under some conditions how
half life = 40minutes =2/3 hourst(1/2)=(ln2 /k)then k=(ln2/t(1/2)) = ln2/(2/3) = 3/2*(ln2)origianl substance y0= 1000 gramsy=y0e-kty= 1000*(e-(3/2(ln2))*2 ) = 1000/8 = 125 grams
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