Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If the roots of the equation (a-b)x2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c.
Ans: (a-b)x2 + (b-c) x+ (c - a) = 0
T.P 2a = b + c
B2 - 4AC = 0
(b-c)2 - [4(a-b) (c - a)] = 0
b2-2bc + c2 - [4(ac-a2 - bc + ab)] = 0
⇒ b2-2bc + c2 - 4ac + 4a2 + 4bc - 4ab = 0
⇒ b2+ 2bc + c2 + 4a2 - 4ac - 4ab= 0
⇒ (b + c - 2a)2 = 0
⇒ b + c = 2a
(6x+9y) + (11x+13y)
what is infinite? ..
prove that every non-trivial ingetral solution (x,y,z)of the diophantine equation Xsquare +Ysquare=Zsquare satisfies gcd(x,y)=gcd(x,z)=gcd(y,z)
probability as that of flipping a coin eight times and getting all the times the same side of the coin.)
Subjective Probability Probability may be determined by a personal statement of how likely an outcome is in a single trial or repetition of the same experiment. Since sub
I didn't understand the concept of Transpose of a Matrix, need assistance.
Q. Finding the Area of a Triangle? There are three commonly used methods to find the area of a triangle. The method you use to find the area depends on the information you kno
Explain the Algebraic Expressions and Equations? Writing a math problem algebraically means that you are using numbers and variables to represent relationships. "Three inche
Determine dy & Δy if y = cos ( x 2 + 1) - x as x changes from x = 2 to x = 2.03 . Solution Firstly let's deetrmine actual the change in y, Δy . Δy = cos (( 2.03) 2
A discrete-valued random variable X takes values in 0, 1, 2, . . . , where p(X = i) = π i. (a) Write down formulas for: the p-value at X = i the probability distributi
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd