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If the roots of the equation (a-b)x2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c.
Ans: (a-b)x2 + (b-c) x+ (c - a) = 0
T.P 2a = b + c
B2 - 4AC = 0
(b-c)2 - [4(a-b) (c - a)] = 0
b2-2bc + c2 - [4(ac-a2 - bc + ab)] = 0
⇒ b2-2bc + c2 - 4ac + 4a2 + 4bc - 4ab = 0
⇒ b2+ 2bc + c2 + 4a2 - 4ac - 4ab= 0
⇒ (b + c - 2a)2 = 0
⇒ b + c = 2a
Find the area of shaded region of circle of radius =7cm, if ∠AOB=70 o , ∠COD=50 o and ∠EOF=60 o . (Ans:77cm 2 ) Ans: Ar( Sector AOB + Sector COD + Sector OEF) = 7
how to do proving of rectilinear figures?..
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Gm signal is better than am signal becuase
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Let a, b, c 2 Z + . (a) Prove that if a|b, then ac|bc for all c. (b) If a|bc, can you conclude that either a|b or a|c? Justify your answer with a proof or a counter example.
Describe the System with 3 Variables ? This is an example of solving a system of equations using the substitution method. Warning: You will not understand this example if you
13 1/4 34 56/89
1. Let M be the PDA with states Q = {q0, q1, and q2}, final states F = {q1, q2} and transition function δ(q0, a, λ) = {[q0, A]} δ(q0, λ , λ) = {[q1, λ]} δ(q0, b, A) = {[q2
simplify the following: 3^5/2-3^1/2
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