Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If the roots of the equation (a-b)x2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c.
Ans: (a-b)x2 + (b-c) x+ (c - a) = 0
T.P 2a = b + c
B2 - 4AC = 0
(b-c)2 - [4(a-b) (c - a)] = 0
b2-2bc + c2 - [4(ac-a2 - bc + ab)] = 0
⇒ b2-2bc + c2 - 4ac + 4a2 + 4bc - 4ab = 0
⇒ b2+ 2bc + c2 + 4a2 - 4ac - 4ab= 0
⇒ (b + c - 2a)2 = 0
⇒ b + c = 2a
how many times can u put 10000 into 999999
Determine the function f ( x ) . f ′ ( x )= 4x 3 - 9 + 2 sin x + 7e x , f (0) = 15 Solution The first step is to integrate to fine out the most general pos
#question.onstruct/draw geometric shapes with specific condition.
in 2000,nearly 18% of cars in north America were sliver. what percent of the cars sold were not sliver?
The functions {sinmx; cosmx}; m = 0,....∞ form a complete set over the interval x ∈ [ -Π, Π]. That is, any function f(x) can be expressed as a linear superposition of these
The length of the diameter of the circle which touches the X axis at the point (1,0) and passes through the point (2,3) is ? Solution) If a circle touches the x-axis, its equatio
create a system of linear equations that has (2,3)as a solution.
what is 24 diveded by 3
you need to cut the proper to cut 2''*4*8 long studs to the proper length to make a finished wall 8" in height underneath the studs there will be a double plate made up of two piec
Geometric Applications to the Cross Product There are a so many geometric applications to the cross product also. Assume we have three vectors a → , b → and c → and we make
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd