Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If the roots of the equation (a-b)x2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c.
Ans: (a-b)x2 + (b-c) x+ (c - a) = 0
T.P 2a = b + c
B2 - 4AC = 0
(b-c)2 - [4(a-b) (c - a)] = 0
b2-2bc + c2 - [4(ac-a2 - bc + ab)] = 0
⇒ b2-2bc + c2 - 4ac + 4a2 + 4bc - 4ab = 0
⇒ b2+ 2bc + c2 + 4a2 - 4ac - 4ab= 0
⇒ (b + c - 2a)2 = 0
⇒ b + c = 2a
A man travels 600km partly by train and partly by truck. If he covers 120km by train and the rest by truck, it takes him eight hours. But, if he travels 200km by train and the res
simple shapes
y+7 3y-2 --- = 1 + ---- 3 5
Awhat is polygonesk question #Minimum 100 words accepted#
what is 0.875 of 2282?
Derive the probability distribution of the completion times: a. The following probability distributions relate to the completion times, in weeks, T A and T B of two independ
how do you solve simultaneous equation?
In traveling three-fourths of the way around a traffic circle a car travels 0.228 mi. What is the radius of the traffic circle? The radius of the traffic circle is ____ mi.
How to get assignment to solve and earn money
Can Slope is calculated as run-rise?
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd