Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If the roots of the equation (a-b)x2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c.
Ans: (a-b)x2 + (b-c) x+ (c - a) = 0
T.P 2a = b + c
B2 - 4AC = 0
(b-c)2 - [4(a-b) (c - a)] = 0
b2-2bc + c2 - [4(ac-a2 - bc + ab)] = 0
⇒ b2-2bc + c2 - 4ac + 4a2 + 4bc - 4ab = 0
⇒ b2+ 2bc + c2 + 4a2 - 4ac - 4ab= 0
⇒ (b + c - 2a)2 = 0
⇒ b + c = 2a
three towns are situated in such away that town B is 120 kilometers on a bearing of 030 degrees from town A. Town C is 210 kilometers on a bearing of 110 degrees from town A (a)ca
Dividing a quantity in a given ratio
76 is 2% of what number?
10000+9854
how to improve managerial skills in hotel?
show that, sin 90 degree = 2 cos 45 degree sin 45 degree
Parametric Curve - Parametric Equations & Polar Coordinates Here now, let us take a look at just how we could probably get two tangents lines at a point. This was surely not
using the g.e matrix, how can you turn an unattractive product to be attractive
General approach of Exponential Functions : Before getting to this function let's take a much more general approach to things. Let's begin with b = 0 , b ≠ 1. Then an exponential f
Consider the subsequent IVP. y' = f(t,y) , y(t 0 ) = y 0 If f(t,y) and ∂f/∂y are continuous functions in several rectangle a o - h o + h which is included in a
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd