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Prove that the area of a rhombus on the hypotenuse of a right-angled triangle, with one of the angles as 60o, is equal to the sum of the areas of rhombuses with one of their angles as 60o drawn on the other two sides.
Ans: Hint: Area of Rhombus of side a & one angle of 60o
= √3/2 x a x a = √3/2 a2
prove that sin A /cot A + cosec A = 2 + sinA / cot A - cosec A
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The lateral edge of a pyramidal church spire is 61feet.Each side of its octagonal base is 22feet. What will be the cost of painting the spire at 2.5 cents a square foot
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