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Prove that the area of a rhombus on the hypotenuse of a right-angled triangle, with one of the angles as 60o, is equal to the sum of the areas of rhombuses with one of their angles as 60o drawn on the other two sides.
Ans: Hint: Area of Rhombus of side a & one angle of 60o
= √3/2 x a x a = √3/2 a2
2 times n times n divided by n
Aim: To test the significant relationship between the accounting ratios of operating management and standard ideal ratios. Null Hypothesis(H 0 ) : There is no significa
Assume that Y 1 (t) and Y 2 (t) are two solutions to (1) and y 1 (t) and y 2 (t) are a fundamental set of solutions to the associated homogeneous differential equation (2) so, Y
2/10
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The points A,B,C and D represent the numbers Z1,Z2,Z3 and Z4.ABCD is rhombus;AC=2BD.if Z2=2+i ,Z4=1-2i,find Z1 and Z3 Ans) B(2,1) , D(1,-2) Mid Point (3/2,-1/2) Write Equati
how does payroll package
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calculate the vector LM given l(4,3),m(-1,2)
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