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Q. Crystal Field Splitting in Octahedral Complexes? Let us consider an octahedral complex, ML6, where M is a metal ion and L stands for a ligand. The total charge on the comple
The third line in Balmer series corresponds to an electronic transition between which Bohr's orbits in hydrogen: (1) 5 → 3 (2) 5 → 2 (3) 4→ 3
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potassium sulphate +copper sulphate = ---
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The following has zero valency : (1) Sodium (2) Beryllium (3) Aluminium (4) Krypton Ans: Krypton
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