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1. Construct an isosceles triangle whose base is 7cm and altitude 4cm and then construct another similar triangle whose sides are 1/2 times the corresponding sides of the isosceles triangle.
2. Draw a line segment AB of length 8cm. taking A as center, draw a circle of radius 4cm and taking B as centre, draw another circle of radius 3cm. Construct tangents to each circle from the center of the other circle.
Standard Basis Vectors Revisited In the preceding section we introduced the idea of standard basis vectors with no really discussing why they were significant. We can now do
The Shape of a Graph, Part I : In the earlier section we saw how to employ the derivative to finds out the absolute minimum & maximum values of a function. Though, there is many
Donald sold $5,250 worth of latest insurance policies last month. If he receives a commission of 7% on new policies, how much did Donald earn in commissions last month? To ?nd
Draw the graph of y=x^2-4x from x=-1 to x=5.use the scale of 2cm on the x axis and 1cm on the y axis.Estimate the gradient at point:x=4, x=2 and x=0
The area of a parallelogram is x 8 . If the base is x 4 , what is the height in terms of x? Since the area of a parallelogram is A = base times height, then the area divided by
Q. Multiplying Fractions Involving Negative Numbers? Ans. If you have only one negative sign, the result is still negative: If you have more than one, just remembe
w/ You could use this sample code to test your C functions // Please make appropriate changes to use this for C++. // Following main function contains 3 representative test cases
Graph f ( x ) = - x 2 + 2x + 3 . Solution It is a parabola in the general form. f ( x ) = ax 2 + bx + c In this form, the x-coor
If tanA+sinA=m and tanA-sinA=n, show that m 2 -n 2 = 4√mn Ans: TanA + SinA = m TanA - SinA = n. m 2 -n 2 =4√mn . m 2 -n 2 = (TanA + SinA) 2 -(TanA - SinA) 2
Extended product rule : As a last topic let's note that the product rule can be extended to more than two functions, for instance. ( f g h )′ = f ′ gh + f g ′ h+ f g h′ ( f
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