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For complex number z, the minimum value of |z| + |z - cosa - i sina|+|z - 2(cosa + i sina )| is..? Solution) |z| + |z-(e^ia)| + |z-2(e^ia)| we see.....oigin , e^ia , 2e^ia , forms a straight line.and for minimum value..... z must coincide with e^iahence the equation becomes:=|e^ia| + 0 + |-e^ia|=1 + 0 + 1=2(ANS)
1+2i=a+ib so find a and b
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