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lbl2lcl2sin2θ
one half y minus 14
How would you solve the equation: 1+ sin(theta)= 2 cos^2(theta)?
explanation
Proof of: lim q →0 (cos q -1) / q = 0 We will begin by doing the following, lim q →0 (cosq -1)/q = lim q →0 ((cosq - 1)(cosq + 1))/(q (cosq + 1)) = lim q
(x+y+1)dy/dx=1
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b2+c2+2bc
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