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Q. Write down a non recursive algorithm to traverse a binary tree in order.
Ans:
Non - recursive algorithm to traverse a binary tree in inorder is as follows:-
Initially in the beginning push NULL onto STACK and then set PTR = ROOT. Then repeat the steps written below until NULL is popped from STACK.
i. Continue down the left -most path rooted at PTR, pushing each node N onto STACK and stopping when a node N with no left child is pushed onto
STACK.
ii. [Backtracking.] Pop and process the nodes on
STACK. If the NULL is popped then Exit. If a node N
Having a right child R(N) is processed, set PTR = R(N) (by assigning PTR = RIGHT[PTR] and return to the Step(a)).
Q. Write down the algorithm which does depth first search through an un-weighted connected graph. In an un-weighted graph, would breadth first search or depth first search or neith
In the last section, we discussed regarding shortest path algorithm that starts with a single source and determines shortest path to all vertices in the graph. In this section, we
Step 1: Choose a vertex in the graph and make it the source vertex & mark it visited. Step 2: Determine a vertex which is adjacent to the source vertex and begun a new search if
[(a+b)/(c+d)^(e+f)]+(g+h)/i
Explain Division Method Division Method: - In this method, key K to be mapped into single of the m states in the hash table is divided by m and the remainder of this division
Easy algorithm for beginner for quicksort with explanation
Write a program to simulate searching over a hashed file, with different assumptions for the sizeof file pages.Write a program to perform equality search operations on the hashed f
Data array A has data series from 1,000,000 to 1 with step size 1, which is in perfect decreasing order. Data array B has data series from 1 to 1,000,000, which is in random order.
Conversion of Forest into Tree A binary tree may be used to show an entire forest, since the next pointer in the root of a tree can be used to point to the next tree of the for
what is frequency count with examble? examble?
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